<span>Assuming the reaction is of 1st order, we can
start using the formula for rate of 1st order reaction:</span>
dN / dt = k * N
Rearranging,
dN / N = k dt
Where N = amount of sample, k = rate constant, t = time
Integrating the equation from N = Ni to Nf and t = ti to
tf will result in:
ln (Nf / Ni) = k (tf – ti)
Since k is constant, we can equate to situations.
Situation 1 is triple in size every days, situation 2 is after 20 days.
ln (Nf / Ni) / (tf – ti) = k
ln (3Ni / Ni) / 4 = ln (Nf / 40) / 20
Calculating for Nf,
<span>Nf =
9,720 bacteria </span>
Answer: Yes, it is less than, as the value of the first equation is 14, while the second equation is 100.8
Step-by-step explanation:
1.7y + 37 = 14...........equation 1
9.3y - 25 = ?............equation 2
Find the value of y by subtracting 37 from both sides of equation 1
1.7y +37 -37 = 14 - 37
1.7y = -23
Divide both sides by 1.7
y = 13.53
Insert the value of y into equation 2
9.3 (13.53) - 25
125.83 -25
=100.8
Answer:
Step-by-step explanation:
81 square yards
Answer:
12 students play chess
and 25 students play Sudoku
Step-by-step explanation:
There are 30 students in Ms Barclay's classroom.
2/5 students play chess.
i.e. 
play chess
i.e. 12 students play chess
5/6 of the students play Sudoku.
i.e. 
play Sudoku
i.e. 25 students play Sudoku
Hence, 12 students play chess
and 25 students play Sudoku
Answer:
A. 2⅓ and D.1
Step-by-step explanation:
We are required to select the values of x that makes the inequality x>½ true.
A. 2⅓
B. 0
C.-1½
D. 1
E.-¾
Options C and E are negative numbers and are therefore less than the positive number ½.
Option B(i.e. 0) is also less than ½ or 0.5 and therefore do not satisfy the inequality given.
Options A and D are greater than ½ and therefore satisfies the inequality given.
