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OLEGan [10]
3 years ago
11

When the following fraction is reduced what will be the exponent on the 27 mn^ 3 / 51 m ^ 6 n​

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

the answer is not 65 and not 4

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I need help finding the slope, The y-intercept, and the equation??
Reil [10]
The slope is 3/4 y intercept is 7
5 0
3 years ago
PLS HELP ASAP!tysm if u help me!<3
Mars2501 [29]

Answer:

Step-by-step explanation:

It is a matter of just substituting the values into the given equation.

4m^2-2n+5

If m=5 and n=9 then it becomes

4(5^2)-2(9)+5

4(25)-18+5

100-18+5

87

6 0
3 years ago
Are the two triangle similar? Pls halp really not good at maths
vladimir2022 [97]
Yes hopefully this helps you
6 0
2 years ago
(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

4 0
2 years ago
Let f(x) = x2 − 8x + 5. Find f(−1).
Westkost [7]
F(x) = x^2 - 8x + 5

f(-1) = -1^2 - 8(-1) + 5
f(-1) = 1 + 8 + 5
f(-1) = 14 <==
3 0
3 years ago
Read 2 more answers
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