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3 years ago

6(2a + b) + b A. 12a + 12b B. 12a + 7b C. 8a + 8b D. 8a – 8b

Mathematics

2 answers:

Nesterboy [21]3 years ago

6 0

Answer:

Step-by-step explanation:

6(2a + b ) +b

12a + 6b +b

12a + 7b

so answer B looks good

icang [17]3 years ago

3 0

Answer: B) 12a+7b

Step-by-step explanation:

6(2a+b) +b

12a+6b+b

Combine like terms

12a+7b

Therefor B is correct

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Solve x2 + 14x + 17 = –96 for x

jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

$ax ^ 2 + bx + c = 0$

The roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

If we have: $x ^ 2 + 14x + 17 = -96$

We can rewrite it in the following way:

$x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0$

Where:

$a = 1\\b = 14\\c = 113$

Where we have:

$x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}$

$x = \frac {-14 \pm \sqrt {(196-452)}} {2}$

$x = \frac {-14 \pm \sqrt {-256}} {2}$

By definition: $\sqrt {-1} = i$

$x = \frac {-14 \pm \sqrt {256} i} {2}$

$x = \frac {-14 \pm16i} {2}$

$x = \frac {-14} {2} \pm \frac {16i} {2}$

$x = -7 \pm8i$

Thus, the roots are given by imaginary numbers:

$x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i$

Answer:

$x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i$

5 0

3 years ago

Read 2 more answers

An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the

nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0

3 years ago

Expand quadratic equation (2x-3)(x+4) = 0

OleMash [197]

Answer:

Step-by-step explanation:

Simplifying

(2x + -3)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(-4 + x) = 0

Multiply (-3 + 2x) * (-4 + x)

(-3(-4 + x) + 2x * (-4 + x)) = 0

((-4 * -3 + x * -3) + 2x * (-4 + x)) = 0

((12 + -3x) + 2x * (-4 + x)) = 0

(12 + -3x + (-4 * 2x + x * 2x)) = 0

(12 + -3x + (-8x + 2x2)) = 0

Combine like terms: -3x + -8x = -11x

(12 + -11x + 2x2) = 0

Solving

12 + -11x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.

(3 + -2x)(4 + -1x) = 0

Subproblem 1

Set the factor '(3 + -2x)' equal to zero and attempt to solve:

Simplifying

3 + -2x = 0

Solving

3 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.

3 + -3 + -2x = 0 + -3

Combine like terms: 3 + -3 = 0

0 + -2x = 0 + -3

-2x = 0 + -3

Combine like terms: 0 + -3 = -3

-2x = -3

Divide each side by '-2'.

x = 1.5

Simplifying

x = 1.5

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying

4 + -1x = 0

Solving

4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0

0 + -1x = 0 + -4

-1x = 0 + -4

Combine like terms: 0 + -4 = -4

-1x = -4

Divide each side by '-1'.

x = 4

Simplifying

x = 4

Solution

x = {1.5, 4}

6 0

3 years ago

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Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of

Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

$\mathbf{L = (0,0)}$

$\mathbf{M = (3,0)}$

$\mathbf{N = (3,7)}$

$\mathbf{O = (0,7)}$

P is the midpoint of LM.

So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

$\mathbf{PQ = \sqrt{ 7^2}}$

$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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2 years ago

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