1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
Answer:
Step-by-step explanation:
sin 30+tan²(60)+sec²(45)
=1/2+ (√3)^2+(√2)²
=1/2+3+2
=5 1/2
=5.5
Answer:
4/25
Step-by-step explanation:
i am pretty sure this is correct:)
Step-by-step explanation:
the function A, according to the tables
=> the equation : f(x) = 2x +3
the slope = 2
the function B, according to the graph
=> the equation : f(x) = 3x -2
the slope = 3
based on the value of the slope, the function B has a greater rate of change
Answer:
A
Step-by-step explanation:
sorry im late
