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Alexus [3.1K]
3 years ago
15

El acido nitrico se obtiene industrialmente por oxidacion de amoniaco (nh3), de acuerdo con la ecuacion: 4nh3 + 702 - h2o + hno2

+ 2hno3 ¿ cuanto acido nitrico del 90% de pureza se podra obtener a partir de 1.36 kg de amoniaco?
Chemistry
1 answer:
devlian [24]3 years ago
6 0

Answer:

2800 g de ácido nítrico

Explanation:

La ecuación por la oxidación de amoniaco es:

4NH₃  +  7O₂  →  4H₂O  +  2HNO₂  +  2HNO₃

Si pensamos que el oxígeno es el reactivo limitante, trabajamos con el amoniaco. Convertimos su masa a moles:

1.36 kg = 1360 g

1360 g . 1mol  /17g = 80 moles

Si 4 moles de amoniaco pueden producir 2 moles de acido nítrico

80 moles producirán, (80 . 2)/4 = 40 moles.

Convertimos los moles a gramos:

40 mol . 63g /mol = 2520 g

Si le aplicamos la pureza

2520 g . 100/90 = 2800 g

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How many solutions are there in the following equation.
givi [52]
When they ask you for the solution they are usually asking for x. So solve for X.
X=-12  so you only have one solution. so the answer is B
6 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
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C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
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C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
3 years ago
? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







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3 years ago
Can someone convert 150 cm of copper (Cu) wire into mm of Cu wire?​
Vedmedyk [2.9K]

1500 mm of copper wire are produced by converting 150 cm of copper wire.

The following is the centimeter to millimeter conversion factor: 1 cm is equivalent to 10 mm.

Consequently, 150 cm will equal 150 x 10 = 1500 mm.

  • The multi-step process of unit conversion involves multiplying or dividing by a numerical factor.
  • Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.
  • Unit conversion is a multi-step procedure that involves adding, subtracting, multiplying, or dividing by a conversion factor.
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To learn more about unit conversion visit:

brainly.com/question/11543684

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6 0
2 years ago
Is density physical or chemical
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Density is a physical
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