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Alexus [3.1K]
3 years ago
15

El acido nitrico se obtiene industrialmente por oxidacion de amoniaco (nh3), de acuerdo con la ecuacion: 4nh3 + 702 - h2o + hno2

+ 2hno3 ¿ cuanto acido nitrico del 90% de pureza se podra obtener a partir de 1.36 kg de amoniaco?
Chemistry
1 answer:
devlian [24]3 years ago
6 0

Answer:

2800 g de ácido nítrico

Explanation:

La ecuación por la oxidación de amoniaco es:

4NH₃  +  7O₂  →  4H₂O  +  2HNO₂  +  2HNO₃

Si pensamos que el oxígeno es el reactivo limitante, trabajamos con el amoniaco. Convertimos su masa a moles:

1.36 kg = 1360 g

1360 g . 1mol  /17g = 80 moles

Si 4 moles de amoniaco pueden producir 2 moles de acido nítrico

80 moles producirán, (80 . 2)/4 = 40 moles.

Convertimos los moles a gramos:

40 mol . 63g /mol = 2520 g

Si le aplicamos la pureza

2520 g . 100/90 = 2800 g

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<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Atmospheric pressure (Pa) = 730.1 torr = 730.1 mmHg
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