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rusak2 [61]
3 years ago
5

the difference of two numbers is 9. if the larger number is one more than twice the smaller number, find the larger number

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

smaller = 8

larger = 17

Step-by-step explanation:

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Please help me i really need help please help please
solong [7]

Answer:

3.605 ft is the answer.

Step-by-step explanation:

Applying Pythagoras theorem,

a^2 + b^2 = c^2

2^2 + 3^2 = c^2

4 + 9 = c^2

13 = c^2

3.605 = c

therefore, the answer is 3.605.

:)

8 0
3 years ago
Plot (25/3) and (42/3) on the number line.
ss7ja [257]

Answer:

Refer to the Attachment

Step-by-step explanation:

Rewriting the fractions in decimal and whole number, we have the following:

\frac{25}{3} = 8\frac{1}{3} = 8.3

\frac{42}{3} = 14

Thus, 42/3 is on 14 and 25/3 is on 8 and then add 1/3 from 8 going to 9.

Therefore, the points must be plotted as follows:

The blue point indicates the 42/3 while the red point indicates the 25/3.

8 0
3 years ago
If (7^ 0)=1what are the possible values of x
olchik [2.2K]
Answer: 1

Explanation: anything to the power of 0 is 1 so if it is x to the power of 0 it would be 1
7 0
3 years ago
Read 2 more answers
Can anyone fill these out?
Tcecarenko [31]

Answer:

Part (a)

36

Part (b)

Find the filled table in the attachment

Part (c)

1/36

Step-by-step explanation:

The total number of possible outcomes using the multiplicative rule is given by;

6*6 = 36.

There are 6 possible outcomes in rolling each die, we simply find the product.

The probability of rolling double sixes is given by;

pr(6 and 6) = pr(6) * pr(6) = 1/6 * 1/6 = 1/36

The probability of rolling double sixes represents independent events and thus we employ the multiplicative rule of probability.

8 0
3 years ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
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