Answer:
Column 1(X) Column 2(mean - X)
125 -13
137 -1
138 0
145 7
145 7
Mean = 138
Mean Absolute Deviation : 5.6
Answer:
36 possible class schedules
Step-by-step explanation:
1st - 4 ways
2nd - 3 ways
3rd - 3 ways
4 x 3 x 3 = 36 possible class schedules
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
We can find area by calculating area of squre with side 27in minus area of square with side12in
You can use Pythagoras theorem to find the radius.
r^2 + 8^2 = 10^2
r^2 + 64 = 100
r^2 = 36
r = 6
