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lutik1710 [3]
2 years ago
6

Prove that if n is an even integer, then n + 1 is odd. Give a proof by contraposition of this theorem.

Mathematics
1 answer:
S_A_V [24]2 years ago
7 0

Answer:

Proved below

Step-by-step explanation:

If we assume that n + 1 even when n is even, it means that;

n + 1 = 2x

Where x is an integer

Then;

n = 2x - 1

This means that n is odd because 2x - 1 is odd.

But we know that n is even, thus, our assumption is wrong.

Therefore, n + 1 is odd when n is even.

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I was told that the answer to this is -7 but I don't understand how to get there.
Amiraneli [1.4K]

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The answer to your question is: - 7

Step-by-step explanation:

                                            3125 = (- 1  - 18t) ⁵/³

                                            (3125)³ = ( -1 - 18t)⁵

                                            (3125)³/⁵ = - 1 - 18t

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                                            126 = - 18t

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                                            t = -7

3125³ = 3.0518 x 10¹⁰

\sqrt[5]{3.0518 x 10¹⁰} = 125

                       

6 0
3 years ago
Help? With this question please
Pie
A. original stuff is for 6 ppl anf u need for 2. and since 2 is 3x less yhan six. divide the ingrefiants by 3.

b. for 15 ppl, 6 is default. dou le all ingtediants is for 12. thrn add 50% more. aka mulyiply all ingrediants by 2.5
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so the answer is : binomial with a degree of 3

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