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lutik1710 [3]
2 years ago
6

Prove that if n is an even integer, then n + 1 is odd. Give a proof by contraposition of this theorem.

Mathematics
1 answer:
S_A_V [24]2 years ago
7 0

Answer:

Proved below

Step-by-step explanation:

If we assume that n + 1 even when n is even, it means that;

n + 1 = 2x

Where x is an integer

Then;

n = 2x - 1

This means that n is odd because 2x - 1 is odd.

But we know that n is even, thus, our assumption is wrong.

Therefore, n + 1 is odd when n is even.

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Step-by-step explanation:

(5z + 15) - (11z + 2)

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= -6z+13

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In circle P, diameter QS measures 20 centimeters
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2 years ago
How can a rational number and irrational number when multiplied together make a irrational number ?
pochemuha

Answer:

"The product of a rational number and an irrational number is SOMETIMES irrational." If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational

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6 0
3 years ago
Which ordered pair makes both inequalities true?
kow [346]

An ordered pair which makes both inequalities true is (-1, -3).

<h3>What is an ordered pair?</h3>

An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.

Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.

For ordered pair (-3, 5), we have:

y < –x + 1

5 < -(-3) + 1

5 < 3 + 1

5 < 4 (False).

For ordered pair (-2, 2), we have:

y < –x + 1

2 < -(-2) + 1

2 < 2 + 1

2 < 3 (True).

y > x

2 > -2 (True)

For ordered pair (-1, -3), we have:

y < –x + 1

-3 < -(-1) + 1

-3 < 1 + 1

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For ordered pair (0, -1), we have:

y < –x + 1

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y > x

-1 > 0 (False)

Read more on inequality here: brainly.com/question/27166555

#SPJ1

5 0
1 year ago
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