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Makovka662 [10]
3 years ago
13

Question 5 (Essay Worth 5 points)

Mathematics
1 answer:
omeli [17]3 years ago
4 0

Answer: 266.7 sq feet


Step-by-step explanation:

Given scale is 1:40 which means 1 inch of rectangle drawn= 40 inches

The length of the room = 40\times6=240\ inches

The width of the room= 40\times4=160\ inches

Now, the area of the rectangular room = length \times width

⇒ The area of the rectangular room=240\times160=38400\ sq\ inches

Also 1 inch=\frac{1}{12}\ feet

Therefore, the area of the rectangular room=\frac{38400}{12\times12}=266.666\approx266.7\ sq feet

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Why can you use cross products to solve the proportion StartFraction 18 over 5 EndFraction = StartFraction x over 100 EndFractio
gtnhenbr [62]

9514 1404 393

Answer:

  it is application of the multiplication property of equality

Step-by-step explanation:

You can use "cross products" to solve any proportion. What looks like a "cross product" is just application of the multiplication property of equality. That property says the variable value is unchanged if both sides of the equation are multiplied by the same value.

For your fraction, the "cross product" is what you get when you multiply both sides of the equation by 500.

  \dfrac{18}{5}=\dfrac{x}{100}\qquad\text{given}\\\\\dfrac{18\cdot5\cdot100}{5}=\dfrac{x\cdot5\cdot100}{100}\qquad\text{multiply by $5\cdot100$}\\\\18\cdot100=5\cdot x\qquad\text{cancel common factors; looks like cross product}

__

Note that the next step here is to divide by the x-coefficient, the 5 that was in the left-side denominator.

  \dfrac{18\cdot100}{5}=x\qquad\text{divide by 5}

Please also note that this is exactly the same result you would get by multiplying the original equation by the original denominator of x.

8 0
3 years ago
Please please help me out
deff fn [24]

Answer:

x = 60°

Step-by-step explanation:

The measure of x is one- half the difference of the measures of the intercepted arcs.

The minor arc = 120°, hence

The major arc = 360° - 120° - 240°, so

x = 0.5(240 - 120) = 0.5 × 120° = 60°

4 0
3 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
1 year ago
the radious of each wheel of a car is 16 inches at how many revolutions per minute should a spin balancer be set to balance the
Alex Ar [27]

Answer:

revolutions per minute for 16 inches is 946 / minute

revolutions per minute for 14 inches is 1081 / minute

Step-by-step explanation:

Given data

radius = 16 inch

speed = 90 mph  = 90/60 = 1.5 miles/minute = 1.5 × 5280 feet /12 inches = 95040 inches /minute

radius 2 = 14 inches

to find out

revolutions per minute

solution

first we calculate the circumference of the wheel i.e. 2×\pi×radius

circumference = 2×\pi×16

circumference = 32\pi

we know that revolution is speed / circumference

revolution = 95040/32\pi

revolution = 945.38 / minute

we have given radius 14 inches than revolution will be i.e.

revolution = speed / circumference

circumference = 2×\pi×14

circumference = 28\pi

revolution =  95040/ 28\pi

revolution = 1080.43 / minute

7 0
3 years ago
During the summer, Bethany mows lawns and Grant is a waiter at a coffee
joja [24]
Both of them could be true, tables and graphs are basically the same thing... is there a photo?
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