9514 1404 393
Answer:
150 square units
Step-by-step explanation:
Each of the six squares has an area of 5×5 = 25 square units. (You can count them, if you wish.)
Then the total area is ...
6×(25 square units) = 150 square units
Answer:
39/37 and 6/5
Step-by-step explanation:
To start, let's assume that 9-8x is positive (we will do this to get rid of the absolute value, but then check later). We get 9(9 - 8x) = 2x + 3, or 81 - 72x = 2x + 3, so 74x = 78 and x = 39/37. If we assume 9-8x is negative, the |9-8x| will turn into 8x-9, so we get 9(8x - 9) = 2x + 3, or 72x - 81 = 2x + 3 , so 70x = 84 and x = 6/5. If we plug the values back in, 9-8(39/37) needs to be positive, which works, and 9-8(6/5) needs to be negative, and this works, so the answers are 39/37 and 6/5.
Answer:
2√10
I hope i am right
Step-by-step explanation:
![(4, 3) (-2, 6)\\Let -the-distance-be ; d\\x_1=4\\x_2 = -2\\y_1 =3\\y_2 =6\\d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^{2} } \\d = \sqrt{(-2-4)^2+(6-4)^{2} } \\d = \sqrt{(-6)^2 +(2)^{2} } \\d = \sqrt{36+4} \\d = \sqrt{40}\\ d = 2\sqrt{10}](https://tex.z-dn.net/?f=%284%2C%203%29%20%20%28-2%2C%206%29%5C%5CLet%20-the-distance-be%20%3B%20d%5C%5Cx_1%3D4%5C%5Cx_2%20%3D%20-2%5C%5Cy_1%20%3D3%5C%5Cy_2%20%3D6%5C%5Cd%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E%7B2%7D%20%7D%20%20%5C%5Cd%20%3D%20%5Csqrt%7B%28-2-4%29%5E2%2B%286-4%29%5E%7B2%7D%20%7D%20%5C%5Cd%20%3D%20%5Csqrt%7B%28-6%29%5E2%20%2B%282%29%5E%7B2%7D%20%7D%20%5C%5Cd%20%3D%20%5Csqrt%7B36%2B4%7D%20%5C%5Cd%20%3D%20%5Csqrt%7B40%7D%5C%5C%20d%20%3D%202%5Csqrt%7B10%7D)
Answer:
16
Step-by-step explanation:
The equation is X2 – 19x + 48 = 0
Using the quadratic formula
X= - b +- √ ( b^2 - 4ac)/ 2a
Where a= 1 b= -19 c= 48
Substitute into the formula we have
CHECK THE ATTACHMENT
HENCE, the solution are 3 and 16
Answer:
3820 years
Step-by-step explanation:
The age of the skull can be found using carbon-14 by applying the half-life relationship.
Age of skull is given by;
![t=(\frac{In\frac{N}{N0} }{-0.693} )*5730](https://tex.z-dn.net/?f=t%3D%28%5Cfrac%7BIn%5Cfrac%7BN%7D%7BN0%7D%20%7D%7B-0.693%7D%20%29%2A5730)
where N=63 N₀=100 -0.693=decay factor of carbon and 5730 =half-life of carbon-14, t =age
substitute values in equation
![t=(\frac{In\frac{63}{100} }{-0.693} )*5730\\\\\\t=(\frac{In0.63}{-0.693} )*5730\\\\\\t=(\frac{ -0.4620}{-0.693} )*5730\\\\\\t=(0.6667)*5730\\\\\\t=3820.29\\\\\\t=3820years](https://tex.z-dn.net/?f=t%3D%28%5Cfrac%7BIn%5Cfrac%7B63%7D%7B100%7D%20%7D%7B-0.693%7D%20%29%2A5730%5C%5C%5C%5C%5C%5Ct%3D%28%5Cfrac%7BIn0.63%7D%7B-0.693%7D%20%29%2A5730%5C%5C%5C%5C%5C%5Ct%3D%28%5Cfrac%7B%20-0.4620%7D%7B-0.693%7D%20%29%2A5730%5C%5C%5C%5C%5C%5Ct%3D%280.6667%29%2A5730%5C%5C%5C%5C%5C%5Ct%3D3820.29%5C%5C%5C%5C%5C%5Ct%3D3820years)