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3 years ago

What is the domain and range of f(x)=2.5x when x goes up to 800

Mathematics

1 answer:

Mandarinka [93]3 years ago

3 0

Answer:

Domain: all real numbers. Range: (-∞, 2000]

Step-by-step explanation:

f(x)=2.5x is a simple "ramp" function, a linear function and a polynomial. As such, its domain contains "all real numbers." That value 800 defines the largest value that this f(x) can have: f(800) = 2.5(800) = 2000.

Thus, the range is "all real numbers from -∞ through and including 2000."

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It says (m-4)(-6) and I have no clue how to solve it

rusak2 [61]

The answer is going to be ((m-6)*-6= -((6 * m-6)).

hope that helped

3 0

2 years ago

In the figure, b and c are parallel lines. Which of the following statements are true?

Helen [10]

Answer:

1. No, Joe is not correct

2. $\angle 5=72^{\circ}$

Step-by-step explanation:

Given: b and c are parallel lines

To find:

1. whether the given statement is correct or not

2. $\angle 5$

Solution:

Sum of two angles that form a linear pair is equal to $180^{\circ}$

$\angle 3+72^{\circ}=180^{\circ}$ (linear pair)

$\angle 3=180^{\circ}-72^{\circ}=108^{\circ}\neq 90^{\circ}$

So, Joe is not correct

If two lines are parallel then alternate interior angles are equal.

As b and c are parallel lines,

$\angle 5=72^{\circ}$ (alternate interior angles)

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2 years ago

An egg was dropped from a 36 foot ladder and took 2.4 seconds to hit the ground. How many feet did the egg travel in 1.5 seconds

ruslelena [56]

Answer:

22,5 ft

Step-by-step explanation:

36÷2,4×1,5=22,5

6 0

2 years ago

A car travels 1/6 of the distance between two cities in 3/5 of an hour. At this rate, what fraction of the distance between the

CaHeK987 [17]

6 if you divide it out

7 0

3 years ago

Find the difference between points M(6,16) and Z(-1,14) to the nearest tenth.

svlad2 [7]

I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: $d=\sqrt{(-1-6)^2+(14-16)^2}$ .