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MaRussiya [10]
3 years ago
10

Find the following expression

Mathematics
1 answer:
kondaur [170]3 years ago
5 0

Answer:

40/30

Step-by-step explanation:

\tan(c)  =  \frac{40}{30}  =  \frac{4}{3}

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THIS IS URGENT! PLZ HELP!
Yanka [14]

Answer:

73

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
4 years ago
Determine the area of a triangle having the following measurements. Round your answer to two decimal places.
Svetllana [295]
Area of a triangle= 1/2 (ab) (sin C) 
                           = 1/2 (9 x 11.5) (sin 63.4) 
                           = 46.27
3 0
3 years ago
The area of a rectangular garden is 7722 m“.
Slav-nsk [51]
The width of the garden is 78
You just divide 7722 by 99 (which is 78)
7 0
3 years ago
Find the volume of each figure. Round your answers to the nearest hundredth, if necessary
SCORPION-xisa [38]

Answer:

666.67π .ft^3

<em>here's</em><em> your</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>radius</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>height</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>πr^</em><em>2</em><em>h</em><em>/</em><em>3</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>radius</em><em> and</em><em> height</em><em> </em>

<em>=</em><em>></em><em> </em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>^</em><em>2</em><em>*</em><em>2</em><em>0</em><em>/</em><em>3</em><em>π</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>6</em><em>6</em><em>6</em><em>.</em><em>6</em><em>7</em><em>π</em><em> </em><em>.</em><em>ft^</em><em>3</em>

<em>hope</em><em> it</em><em> helps</em>

5 0
3 years ago
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