Factor the trinomial below

Once the Mercury-Atlas 9 was in orbit, in the first 20 seconds the spacecraft traveled 156km. What was the acceleration of the s

Shkiper50 [21]

Spacecraft once the 20 seconds space

6 0

3 years ago

Which of the following equations have exactly one solution?

Licemer1 [7]

I need to see a picture of the question so I can answer the question:)

5 0

3 years ago

A line of best fit predicts that when x equals 28, y will equal 27.255, but y actually equals 26. What is the residual in this c

zlopas [31]

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value = 26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

5 0

2 years ago

Mike jogged a total distance of 5 1/3 miles during the months of October and November. If Mike only jogger 1/6 mile every day, W

Bumek [7]

Answer:

D

Step-by-step explanation:

If he jogged $x$ miles every day, and he jogged a total distance of $y$ miles, then he runs for $y/x$ days. This is an extension of the $d=rt$ or distance equals rate times time.

We plug in for y and x to get that he runs for $5~1/3~~/~~1/6$ .

So, the answer is $\boxed{D}$ and we're done!

7 0

2 years ago

Read 2 more answers

A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining th

Anuta_ua [19.1K]

These are two questions and two answers:

Question 1:

A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work.

Answer: The negative value of the radicand means that the equation does not have real solutions.

Explanation:

1) With radicand the statement means the disciminant of the quadratic function.

2) The discriminant is: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation: ax² + bx + c

3) Then, for 3x² - 15x + 20, a = 3, b = - 15, and c = 20

and the discriminant (radicand) is: (-15)² - 4(3)(20) = 225 - 240 = - 15.

4) The negative value of the radicand means that the equation does not have real solutions.

Question 2:

Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answer: two solutions x = 1 and x = - 8/3x

Explanation:

1) I choose factoring (you may use the quadratic formula if you prefer)

2) Factoring

Given: 3x² + 5x − 8 = 0

Make 5x = 8x - 3x: 3x² + 8x - 3x - 8 = 0

Group: (3x² - 3x) + (8x - 8) = 0

Common factors for each group: 3x(x -1) + 8(x - 1) = 0

Coomon factor x - 1: (x - 1) (3x + 8) = 0

The two solutions are for each factor equal to zero:

x - 1 = 0 ⇒ x = 1
3x + 8 = 0 ⇒ x = -8/3

Those are the two solutions. x = 1 and x = - 8/3

4 0

3 years ago