By evaluating the linear equation, we can complete the table:
x: -2 | -1 | 0 | 1 | 2 |
y: -3 | -1 | 1 | 3 | 5 |
<h3>
How to complete the given table?</h3>
Here we want to complete the table:
x: -2 | -1 | 0 | 1 | 2 |
y: | | | | |
To get the correspondent values in the "y" row, you just need to evaluate the linear function in the given values of x.
Here the function is:
f(x) = 2x - 1
Evaluating it we get:
f(-2) = 2*(-2) + 1 = -3
f(-1) = 2*(-1) + 1 = -1
f(0) = 2*0 + 1 = 1
f(1) = 2*1 + 1 = 3
f(2) = 2*2 + 1 = 5
Now we just put these values in their correspondent place on the table.
x: -2 | -1 | 0 | 1 | 2 |
y: -3 | -1 | 1 | 3 | 5 |
If you want to learn more about linear functions:
brainly.com/question/1884491
#SPJ1
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables 
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that 
We need to proof that 
by the definition of binomial random variable then we need to show that:
The deduction is based on the definition of independent random variables, we can do this:
And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor 
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that
(a) 28%
(b) 24%
When calculating the total amount of people it come out to 150.
According to the table 42 people smoke. 42/150 is 28%
According to the table 36 people exercise regularly. 36/150 is 24%
