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Rufina [12.5K]
4 years ago
5

Multiply (3.2 x 103) x (1.5 x 103)

Mathematics
2 answers:
Mekhanik [1.2K]4 years ago
3 0

Answer:

50923.2

Step-by-step explanation:

↑↑↑

igor_vitrenko [27]4 years ago
3 0
I think I’m not too sure 484.1
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A CONE IS 1/3 OF A CYLINDER, SO THE VOLUME FORMULA IS 1/3 THE CYLINDER. True or false
aleksandrvk [35]

Answer:

yes that's the answer because the volume of a cylinder= πr²h and the volume of a cone =1/3πr²h

7 0
3 years ago
3! + 4! = 5040 30 or 16
makkiz [27]

Answer:

None of those

Step-by-step explanation:

3! = 3*2*1 = 6

4! = 4*3*2*1 = 24

24 * 6 = 144

144 is none of the choices

6 0
3 years ago
Read 2 more answers
Laura jog around the soccer field that 80m by 120m.how many yards does she goes around the field two times?​
exis [7]

A rectangle has two couples of equal sides, so a soccer fields has two 80-meters sides and two 120-meters sides.

This leads to a perimeter of

120+120+80+80=400 \text{ m}

If you go around it twice, you'll run 800 meters

8 0
4 years ago
A parent died and left an estate to four children. One inherited 1/2 of the estate, the second inherited 1/8, and the third inhe
Inessa [10]
1/2 is 4/8
4/8+1/8+1/8=6/8
what's left is 2/8, which is 1/4
7 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
4 years ago
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