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3 years ago

Which are true about area of a circle? Check all that apply

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

The units are always squared. The area can be found when given the diameter by first finding the radius. Circumference can be used to find area

Step-by-step explanation:

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Tom worked at Home Depot over the summer and saved $2,000. He invested his earnings in an account that paid 4.5% interest compou

yuradex [85]

I believe the result would be about $2,282.80 dollars. It might have some extra cents added to it but this is about the correct answer.

2000 * 0.045 = 90 + 2000 = 2090

2090 * 0.045 = 94.5 + 2090 = 2282.80

2184.5 * 0.045 = 98.30 + 2184.5 = $2282.80

2282.80 is the answer.

Hope this Helps!!

Mark Brainiest Please!!!!!

3 0

3 years ago

What is the y-intercept of this line?<br> y = x - 2<br> b = [?]

Nostrana [21]

Answer:

-2

Since b = -2, the y intercept is -2.

4 0

2 years ago

Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.

GalinKa [24]

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = $x$

m∠D = $2x-20$ °.

Now, let m∠A = m∠B = $y$

So, m∠C = m∠A + 30° = $y+30$

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B + m∠C = 180

$y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50$

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

$2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50$

Therefore, m∠F = 50°

m∠E = 50° and

m∠D = $2x-20=2(50)-20=100-20=80\°$

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

5 0

3 years ago

Number two please <br> ASAP

miv72 [106K]

The solutions for $-5 +2x^{2} = -6x$ is option 3. $x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of $ax^{2} +bx +c =0.$

So $-5 +2x^{2} = -6x$ becomes $2x^{2} +6x-5=0.$

The value of a is the coefficient of the $x^{2}$ term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to $ax^{2} +bx +c =0,$ we get $a = 2, b = 6,$ and $c=-5.$

We have the formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.$

Step 2:

By substituting the known values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.$

$\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

This is the third option.

8 0

4 years ago

The marked price of a water cooler is $ 500. The shopkeeper offers an off-season discount of 15% on it. Find the discount.

Fittoniya [83]

Answer:

75 dollars

Step-by-step explanation:

You know that 500=100%, so we can set up the following

15%(500/100%) = 75

so the discount 75 dollars

5 0

3 years ago