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kondor19780726 [428]
3 years ago
10

I need help on number 10 urgently.

Mathematics
2 answers:
grigory [225]3 years ago
6 0

Answer: Option A. 288 cubic inches

uranmaximum [27]3 years ago
4 0

The formula for the volume of a cylinder is

V = π · R² · Height .

The formula for the volume of a sphere is

V = 4/3 · π · R³ .

We <u>know</u> the volume of the cylinder, so let's work with that formula, and see if we can squeeze anything out of it that can help us with the sphere.

Cylinder:  V = π · R² · Height .

Wow !  Look at the picture for a second !  The radius of the cylinder is the same as the radius of the sphere, AND the height of the cylinder is double the radius !  This should really help.

Cylinder:  V = π · R² · (2R) .

V = π · (2R³)

But we know the volume of the cylinder.  It's  432π inch³ .

432π in³ = π · 2R³

Divide each side by  2 :

π R³ = 216 in³

We could use this to find the radius, but why bother ?  Why not just keep (π R³) and stuff it straight into the formula for the volume of the sphere ! ?

Sphere:  V = 4/3 · (π · R³)

V = 4/3 · (216 in³)

V = (4/3 · 216) in³

<em>V = 288 in³ </em><em> </em>

<em />

Ahhh ... the sweet feeling of knowing that you're right !

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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
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3 years ago
Please help explain how to solve problem 16?
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Here is the problem.....√(15x + 10) = 2x+3

to remove the square root, we do the opposite which is to square everything.

(√(15x + 10))² = (2x + 3)²      (the square negates the square root)
15x + 10 = (2x +3)(2x + 3)    (use the distributive property to continue)
15x + 10 = 4x² + 6x + 6x + 9  (combine like terms)
15x + 10 = 4x² + 12x + 9      (subtract 15x and 10 from each side)
-15x - 10          -15x - 10
0 = 4x² - 3x - 1                      (factor completely)
(x - 1) (4x + 1)                    (set each to equal 0)

x - 1 = 0                4x + 1 = 0
x = 1                      4x = -1
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place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.

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