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kifflom [539]
3 years ago
9

In the expression 3y•10 what is coefficient

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

3

Step-by-step explanation:

A coefficient is a numerical factor that contains a variable.

In this case, 3 is a numerical factor and contains a variable (y).

Hence,

3 is the coefficient of the expression.

You might be interested in
Which shows all the critical points for the inequality x2-4/x2-5x+6<0
Hoochie [10]

Answer:

x = ±2, 3 are the critical points of the given inequality.

Step-by-step explanation:

The given inequality is \frac{(x^{2}- 4)}{x^{2}-5x+6}

To find the critical points we will equate the numerator and denominator of the inequality to zero.

For numerator,

x^{2}-4=0

(x - 2)(x + 2) = 0

x = ±2

For denominator,

x² - 5x + 6 = 0

x² - 3x -2x + 6 = 0

x(x - 3) -2(x - 3) = 0

(x - 3)(x - 2) = 0

x = 2, 3

Therefore, critical points of the inequality are x = ±2, 3 where the sign of the inequality will change.

7 0
3 years ago
Sunflower produce approximately 50 seeds per flower. If one ounce of sunflower seeds contain an average of 72 seeds, how many fl
ra1l [238]

Given :

Sunflower produce approximately 50 seeds per flower.

If one ounce of sunflower seeds contain an average of 72 seeds.

To Find :

How many flowers are needed to produce 2 pounds of seeds.

Solution :

1 pound = 16 ounces .

So , 2 pound = 32 ounces .

Number of seeds in 2 pounds of seeds, n = 32×72 = 2304 .

Number of flowers are :

N=\dfrac{2304}{50}=46.08

So , approximate number of flower required are 46.

Hence, this is the required solution.

5 0
3 years ago
If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices
kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Then the inverted version of transposed A is

(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

The inverted version of A is:

A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]

The transposed version of inverted A is:

(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

We can see that

(A^T)^{-1} = (A^{-1})^T

So this theorem is true for 2 x 2 matrices

3 0
3 years ago
Evaluate 1x + y, for x = 8 and y=-15.<br> 7 <br> -7<br> 23<br> -23
statuscvo [17]

Answer:

B) -7

Step-by-step explanation:

x+y

8+(-15)=8-15=-7

5 0
3 years ago
What is the variable of 18+t
Dmitry_Shevchenko [17]
T because all variables are letters
6 0
3 years ago
Read 2 more answers
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