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frozen [14]
3 years ago
9

Cape Hatteras Lighthouse was built in 1870 and rises 208 feet above sea level. From the top of the lighthouse, the lighthouse ke

eper observes two ships along the same line of sight. The angle of depression to ship 1 is 20  and the angle of depression to ship 2 is 12.5  . For safety purposes, the keeper thinks the two ships should be at least 300 feet apart. If they are less than 300 feet apart, she will sound a warning. How far apart are the vessels? Will she sound the warning?

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

The distance between them is 366.75 feet.

She doesn't need to sound a warning yet.

Step-by-step explanation:

Please see the attached files for explanation.

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Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (N
prisoha [69]

Answer:

The solution to this system of equations is:

  • B = 28
  • T = 19

Step-by-step explanation:

We are given that Jill has 47 bugs and counts a total 320 legs.

We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

\text{tarantulas + butterflies} = 47

We are also told that T is tarantulas and B is butterflies.

T + B = 47

Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

6B + 8T = 320

Now, we can set up a system of equation.

\displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.

Using the first equation, we can solve for B.

\displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T

Then, we can substitute this value of B into the second equation and solve for T.

\displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19

Finally, we can substitute this value of T into the first equation to solve for B.

B + 19 = 47\\\\B + 19 - 19 = 47 - 19\\\\B = 28

Therefore, the solution to this system of equations is:

  • B = 28
  • T = 19
7 0
3 years ago
5 Exam-style ABCD is a kite.
Mnenie [13.5K]

let's recall that in a Kite the diagonals meet each other at 90° angles, Check the picture below, so we're looking for the equation of a line that's perpendicular to BD and that passes through (-1 , 3).

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of BD

y = \stackrel{\stackrel{m}{\downarrow }}{3}x-1\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line whose slope is -1/3 and passes through point A

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-1)}]\implies y-3=-\cfrac{1}{3}(x+1) \\\\\\ y-3=-\cfrac{1}{3}x-\cfrac{1}{3}\implies y=-\cfrac{1}{3}x-\cfrac{1}{3}+3\implies y=-\cfrac{1}{3}x+\cfrac{8}{3}

5 0
3 years ago
A delivery truck is transporting boxes of two sizes: large and small. The combined weight of the large box and a small box is 70
andre [41]

Answer:

3.45

Step-by-step explanation:

you have to do tihis then that

3 0
3 years ago
4/5x+5=9 solve for x please i have 8 questions left!!!!!!!!!!!
NemiM [27]

Answer:

x= 5

Step-by-step explanation:

You need to get rid of the fraction first and to do that you muliply the whole equation by 5 so that your new equation reads 4x+25=45. Then you subtract 25 from both sides so you have 4x=20. Divide both sides by 4 so x=5.

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robert has money in his saving account. he spent $35 of it on a new jacket. he has $70 left. how much money did he have his savi
aliina [53]
He had $105 in his savings
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