Answer:
<h2>
D.84</h2>
Step-by-step explanation:
<u>*It's an isosceles triangle so 2 of the angles are going to be the same degrees</u>
<u>*Every triangle is 180 degrees</u>
(48)+(48)=96 then 180-96=84
If the volume of the aluminum brick will be 2218.5 cubic cm. Then the approximate density of the aluminum will be 8.9 grams per cubic cm.
<h3>What is density?</h3>
Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
The mass and density relation is given as
Density = mass/volume
A brick of aluminum weighs 19,745 grams and has the following dimensions: length 29 cm, height 15 cm, and width 51 mm.
Then the approximate density of the aluminum will be
The volume of the aluminum brick will be
V = 29 x 15 x 5.1
V = 2218.5 cubic cm
Then the density will be
D = 19,745 / 2218.5
D = 8.900 gram per cubic cm
To learn more about the density refer to the link;
brainly.com/question/952755
#SPJ1
Definitely, its volume is greater than the original cylinder. Hope it help!
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
1 7/6 = 2 1/6 hope this helps brainliest please:))
