A pile of coins, consisting of quarters and half dollars, it worth $11.75. If there are 2 more quarters than half dollars, how m
any of each are there?
1 answer:
Let the number of half dollars be x,
number of quarters = x + 2
amount of half dollars = 0.5x
amount of quarters = 0.25(x + 2)
= 0.25x + 0.5
total amount = 0.5x + 0.25x + 0.5
= 0.75x + 0.5
0.75x + 0.5 = 11.75
0.75x = 11.25
x = 15
number of quarters = x + 2
= 15 + 2
= 17
There are 17 quarters and 15 half dollars.
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Solution:
<u>Note that:</u>
- Han's house = 450 m from school
- Lin's house = (450 - 135) from school
<u>Looking at the options, we can tell that the letter "z" represents Lin. </u>
- => z = (450 - 135)
- => z = 450 - 135
This option matches with Option D.
Option D is correct.
Answer:
200
Step-by-step explanation:
Answer:
I don't know sorry
it is clear that this is not online class
First write the equation:
1/2x + 5 = 6
Then subtract five from both sides:
1/2x = 1
Multiply both sides by 2:
x = 2
6x to the power of 2
6x^2
Answer: 36x