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anzhelika [568]
2 years ago
8

if bought 15 caterpillars for $3.00, how much was each caterpillar (find the unit rate for price per caterpillar)

Mathematics
2 answers:
pishuonlain [190]2 years ago
7 0

Answer:

<em>$</em><em>0.20</em>

COST OF 15 CATERPILLAR=$3

THEREFORE COST OF ONE CATERPILLAR =$3/15=$1/5=$0.20

Mashutka [201]2 years ago
3 0

Answer:

20 cents

Step-by-step explanation:

Divide 3 dollars by 15 caterpillars.

3/15 = 0.2

20 cents

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So go down 1 below 0.

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So -2 is our slope. It will be -2/1 because we need a fraction to graph the rise over run and all whole numbers can be a fraction by making 1 as their denominator.

Look at the attachment. 

Starting from -1 (y-intercept), go down 2 (-2) then right 1 (1).
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3 years ago
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yulyashka [42]

Answer:

r=-6

Step-by-step explanation:

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8 0
3 years ago
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IRINA_888 [86]

Answer:

<em>Answer is option</em><em> </em><em>b</em><em>)</em><em> </em>

<em>{(x - 3)}^{2}  +  {(y - 4)}^{2}  = 400</em>

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Step-by-step explanation:

the \: question \: states \: that \:  \\ distance \: between \: two \: points \: is \: 20 \: units \:  \\ and \: the \: two \: points \: are \: (x,y) \:  \: and \:  \: (3 ,- 4) \\ distance \: formula \\  =   \sqrt{ {(x1 - x2) }^{2} +  {(y1 - y2)}^{2}  }  \\ on \: substituting \: the \: values \: in \: formula \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y - ( - 4))}^{2}  }  \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y + 4)}^{2}  }  \\ now \: squaring \: on \: both \: sides \\ 400 =  {(x - 3)}^{2}  +  {(y + 4)}^{2}  \\ hence \: the \: answer \: is \: option \: b)

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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PIT_PIT [208]
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Answer:

Sure I'll try to help!

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Step-by-step explanation:

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