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3 years ago

What is the value of x?

Mathematics

2 answers:

Degger [83]3 years ago

8 0

Answer:

The correct answer would be B. 10

Step-by-step explanation:

6^2 + 8^ = c^2

36 + 64 = 100

6 + 8 + 1 0

nalin [4]3 years ago

5 0

The answer is 10 i think

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2 years ago

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Victoria rides her bike at a constant rate of 1 3/8 miles every 1/4 hour. What is her speed in miles per hour?

NISA [10]

Answer:

5 1/2 miles per 1 hr

Step-by-step explanation:

biked 1 3/8 miles in 1/ of an hour

1 3/8 miles = 11/8 miles in 1/4 of hour

11/8 miles divided by 1/4 hr

11/8 ÷ 1/4

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6 0

3 years ago

Which of the following is the interest on $6000 at 6% compounded semiannually for eight years?

ryzh [129]

Answer:

$3628.24

Step-by-step explanation:

we use the formula for accrued value (A) with compounded interest:

$A=P(1+\frac{r}{n})^{n*t}$

where A= accrued value (principal plus the accumulated interest)

P = principal -> in our case $6000

r = annual interest rate (in decimal form) -> in our case 0.06

n = number of compoundings per year. In our case 2 (semiannually)

t = time in years -> in our case 8

$A=P(1+\frac{r}{n})^{n*t}\\A = 6000(1+\frac{0.06}{2})^{16}\\ A= 6000(1+0.03)^{16}\\A = $9628.24$

Since this is the value of principal plus accumulated interest, we subtract from it the principal ($6000) to get the value of just the interest:

$9628.24 - $6000 = $3628.24

4 0

3 years ago

Complete 6,7 for 5 points.

seraphim [82]

Answer:

idk the answer

Step-by-step explanation:

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3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

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3 years ago