The present age of mother and her daughter respectively are; 40 and 10 years respectively.
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Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
Step-by-step explanation:
A. Every month Population will increase by a factor of 0.84%.
B. Every 3 months Population will increase by a factor of 2.5%.
C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.
<u>Step-by-step explanation:</u>
Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as
which is equivalent to
.
<u>A.</u>
For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like
. ∴ Every month Population will increase by a factor of 0.84%.
<u>B.</u>
In every 3 months: We have , 12 months in a year , in order to check for every 3 months
and Now, Population increase in every 3 months is
. ∴ Every 3 months Population will increase by a factor of 2.5%.
<u>C.</u>
In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.
So , increase in population in every 20 months is 10% + 6.72% = 16.72%.
25,*55**3,552
*is the digit in the hundred thousand place
**is the digit that has 1/1000 the value of the digit.
(*) indicates the number after the *.
I doubled check this work, but I will update comment with a triple check