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Ksivusya [100]
3 years ago
8

The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 8 

cm and a second side that is 4 cm less than twice the third side, what are the possible lengths for the second and third sides?
Mathematics
1 answer:
julsineya [31]3 years ago
3 0
Good afternoon, 

First side= 8cm 
Third side= x
Second side= 2x-4

We know that the sume of the lenghts of any two sides must be greater than the third side, so:

Second \,\,\,\,side+Third\,\,\,\,side>First\,\,\,\,side \\ 2x-4 + x >8 \\ 3x>12 \\ x>4


<span>Answer: Third side= x                        ;         where: x>4 or (4,+infinity)
                Second side= 2x-4              ;        </span><span> where: x>4 or (4,+infinity)</span>
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B= 1, 1 1/2, 2, 4

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7 0
3 years ago
A rectangle has an area of 45x2 − 42x − 48 and a width of 5x − 8. what is the length of the rectangle? to find the length of the
kondaur [170]

If the area and width of the rectangle are 45x² − 42x − 48 and (5x − 8) then the length of the rectangle will be (3x + 2).

<h3>What is a rectangle?</h3>

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rectangle, opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at the mid-point.

A rectangle has an area of 45x² − 42x − 48 and a width of 5x − 8.

Then the length of the rectangle will be

area = length × width

Then we have

Area = 45x² − 42x − 48

Then the factor of the polynomial will be

Area = (5x − 8)(3x + 2)

Then the length of the rectangle will be (3x + 2).

More about the rectangle link is given below.

brainly.com/question/10046743

4 0
2 years ago
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Help me, please! I will mark the brainiest! ANY OFF TOPIC ANSWER WILL BE DELETED!
Lynna [10]
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3 years ago
Identify the digit with the given place value in number 173.514 hundredths
Llana [10]

Answer: We are given the number 173.514

Each of the digits in this number has the following place value:

\begin{gathered} 1\rightarrow\text{ Hundreds} \\ 7\rightarrow\text{ Tens} \\ 3\rightarrow\text{ Ones} \\ \text{.}\rightarrow\text{  Decimal Point} \\ 5\rightarrow\text{ Tenth} \\ 1\rightarrow\text{  Hundreth} \\ 4\rightarrow\text{  Thousandth} \end{gathered}

Secondly, We have to identify the numbers in digit 185.712

\begin{gathered} 1\rightarrow\text{ Thousand} \\ 8\rightarrow\text{ Hundred} \\ 5\rightarrow\text{ Tens} \\ \text{. Decimal point} \\ 7\text{ }\rightarrow\text{Thenth} \\ 1\rightarrow\text{ Hundreth} \\ 2\text{ }\rightarrow\text{ Thousandth} \\  \end{gathered}

5 0
1 year ago
What is the rounding or compatible number<br><br> of 256+321
Nana76 [90]
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)


4 0
3 years ago
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