Question

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Answer 1

Given:

The expression is:

$\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)$

To find:

The missing values in the simplification of the given expression.

Solution:

We have,

$\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)$

Combining like terms, we get

$\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\left(\dfrac{6}{17}t+\dfrac{7}{17}t\right)+\left(-6+9\right)$

$\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\dfrac{13}{17}t+3$

Therefore, the missing values for 1,2,3,4 blanks are $\dfrac{6}{17}t,9,\dfrac{13}{17},3$ respectively.