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Gnoma [55]
3 years ago
8

Negative two and one-fourth divded by negative one and one-half

Mathematics
1 answer:
Bond [772]3 years ago
3 0

Answer:

The answer is 3/2 or 1 1/2

Step-by-step explanation:

First, you have to make it as a improper fraction :

- 2 \frac{1}{4}

=   - \frac{( 2 \times 4) + 1}{4}

=  -  \frac{9}{4}

- 1 \frac{1}{2}

=  -  \frac{(1 \times 2) + 1}{2}

=  -  \frac{3}{2}

Next, you can divide it by cutting out the common factor :

-  \frac{9}{4}  \div  -  \frac{3}{2}

=  -  \frac{9}{4}  \times -   \frac{2}{3}

=   - \frac{  3}{2}  \times  - 1

=  \frac{3}{2}

= 1 \frac{1}{2}

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The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
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y(t) = 275 - 16*t^2.

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AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

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The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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