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Gnoma [55]
3 years ago
8

Negative two and one-fourth divded by negative one and one-half

Mathematics
1 answer:
Bond [772]3 years ago
3 0

Answer:

The answer is 3/2 or 1 1/2

Step-by-step explanation:

First, you have to make it as a improper fraction :

- 2 \frac{1}{4}

=   - \frac{( 2 \times 4) + 1}{4}

=  -  \frac{9}{4}

- 1 \frac{1}{2}

=  -  \frac{(1 \times 2) + 1}{2}

=  -  \frac{3}{2}

Next, you can divide it by cutting out the common factor :

-  \frac{9}{4}  \div  -  \frac{3}{2}

=  -  \frac{9}{4}  \times -   \frac{2}{3}

=   - \frac{  3}{2}  \times  - 1

=  \frac{3}{2}

= 1 \frac{1}{2}

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3 years ago
Help please im lost and not good in math
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What is the work for 309÷76,255
Ber [7]
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5 0
2 years ago
If
Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}

Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

5 0
2 years ago
What is 70% of blank = 28
QveST [7]
Percent means parts out of 100
70%=70/100=7/10
7/10 of x=28
'of' means multiply
7/10 x=28
multiply both sides by 10/7 to get rid of fraciton
x=40


the number is 40
5 0
3 years ago
Read 2 more answers
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