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3 years ago

Maths equation need help please

Mathematics

1 answer:

Olin [163]3 years ago

7 0

Answer:

I FIGURED IT OUT!

Step-by-step explanation:

a = 3

b = 3

c = 5

d = 2

give me brainliest

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Find the GCF of 56 and 46<br> a)8<br> b)2<br> c)10

Elis [28]

Answer: 2

8: 8,16,24,32,40,48,56,64

2: 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60

10: 10,20,30,40,50,60,70,80

As you can see when skip counting 2's you have the numbers 56 and 46. Therefore the GCF of 56 and 46 is 2.

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How do you answer this??

dezoksy [38]

<h3>Given</h3>

a rectangle x units wide and y units high divided into unit squares

The total perimeter of the unit squares, counting each line segment once

<h3>Solution</h3>

For each of the y rows of squares, there are x segments at the top, plus another x segments at the bottom. The total number of horizontal segments is then

... horizontal segment count = (y +1)x

Likewise, for each of the x columns of squares, there are y segments to the left, plus another y segments to the right of the entire area. Then the total number of vertical segments is

... vertical segment count = (x+1)y

The total segment count is ...

... total segments = horizontal segments + vertical segments

.. = (y+1)x +(x+1)y

... total segments = 2xy +x +y

_____

<u>Check</u>

We know a square (1×1) has 4 segments surrounding it.

... count = 2·1·1 +1 +1 = 4 . . . . (correct)

We know the 3×3 window in the problem statement has 24 segments.

... count = 2·3·3 +3 +3 = 18 +3 + 3 = 24 . . . . (correct)

We know a 1×3 row of panes will have 10 frame elements.

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It looks like our formula works well.

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Nuetrik [128]

The second one is B

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