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BartSMP [9]
3 years ago
11

Laura is the first person in her SDLC team to detect and predict security vulnerabilities in the software. In which phase is Lau

ra involved?
A.
analysis
B.
design
C.
development
D.
testing
E.
implementation
Computers and Technology
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

answer is c

if my answer is wrong than sorry

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What should you do if your computer is running slower
Norma-Jean [14]

Answer:

Update system and files. Also delete unnecessary apps taking space

3 0
3 years ago
Complete the following Programming Assignment using Recursion. Use good programming style and all the concepts previously covere
Likurg_2 [28]

Answer:

Explanation:

public class Ackermann {

   public static int ackermann's(int m, int n) {

       if (m == 0) {

           return n + 1;

       } else if (n == 0) {

           return ackermann's(m-1, 1);

       } else {

           return ackermann(m - 1, ackermann(m, n - 1));

       }

   }

   public static void main(String[] args) {

       System.out.println(ackermann(0, 0));

       System.out.println(ackermann(0, 1));

       System.out.println(ackermann(1, 1));

       System.out.println(ackermann(1, 2));

       System.out.println(ackermann(1, 3));

       System.out.println(ackermann(2, 2));

       System.out.println(ackermann(3, 2));

   }

}

1

2

3

4

5

6

7

29

Process finished with exit code 0

6 0
3 years ago
What OC level is primarily used as a regional isp backbone, and occasionally by very large hospitals, universities, or other maj
Neporo4naja [7]

The OC level is primarily used as a regional ISP backbone, and occasionally by very large hospitals, universities, or other major enterprises is <u>OC-48.</u>

<u></u>

<h3>What is the greatest amount of throughput provided by an OC 12?</h3>

OC-12 is a network line with communication speeds of up to 622.08 Mbit/s (payload: 601.344 Mbit/s; overhead: 20.736 Mbit/s). OC-12 lines are generally used by ISPs as wide area network (WAN) connections.

<h3>When using frame relay What is the appellation of the identifier?</h3>

A data-link connection identifier (DLCI) determines the Frame Relay PVC. Frames are routed through one or more virtual circuits determined by DLCIs.

Each DLCI has a permanently configured switching path to a particular destination

To learn more about OC level , refer

brainly.com/question/25899244

#SPJ4

<u></u>

5 0
2 years ago
Prompt the user to enter four numbers, each corresponding to a person's weight in pounds. Store all weights in a list. Output th
Lesechka [4]

Answer:

# FIXME (1): Prompt for four weights. Add all weights to a list. Output list.

weight_one=float(input('Enter weight 1:\n'))

weight_two=float(input('Enter weight 2:\n'))

weight_three=float(input('Enter weight 3:\n'))

weight_four=float(input('Enter weight 4:\n'))

weights=[weight_one,weight_two,weight_three,weight_four]

print(weights)

# FIXME (2): Output average of weights.

average_weight=(weight_one + weight_two + weight_three + weight_four) / 4

print('Average weight:', "%.2f" % average_weight)

# FIXME (3): Output max weight from list.

weights.sort()

max_weight= weights[3]

print('Max weight:', "%.2f" % max_weight)

# FIXME (4): Prompt the user for a list index and output that weight in pounds and kilograms.

print(input('Enter a list index location (0 - 3):'))

print('Weight in pounds:', weights)

kilograms = float(weights) * 2.2

print('Weight in kilograms:')

# FIXME (5): Sort the list and output it.

weights.sort()

print(weights)

Explanation:

6 0
3 years ago
Lists and Procedures Pseudocode Practice For each situation, provide a pseudocoded algorithm that would accomplish the task. Mak
Andrei [34K]

Answer:

The pseudocoded algorithm is as follows:

Procedure sumOdd(lotsOfNumbers):

    oddSum = 0

    len = length(lotsOfNumbers)

    for i = 0 to len - 1

         if lotsOfNumbers[i] Mod 2 != 0:

              OddSum = OddSum + lotsOfNumbers[i]

Print(OddSum)

Explanation:

This defines the procedure

Procedure sumOdd(lotsOfNumbers):

This initializes the oddSum to 0

    oddSum = 0

This calculates the length of the list

    len = length(lotsOfNumbers)

This iterates through the list

    for i = 0 to len-1

This checks if current list item is odd

         if lotsOfNumbers[i] Mod 2 != 0:

If yes, the number is added to OddSum

              OddSum = OddSum + lotsOfNumbers[i]

This prints the calculated sum

Print(OddSum)

6 0
3 years ago
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