A teenager has 8 tee shirts, 2 belts, and 5 pairs of jeans. How many different outfits can he wear, assuming that he must wear a
belt to keep those pants up and keep that shirt tucked in?
1 answer:
Answer: 80 ways
Step-by-step explanation:
If 8 tee shirts can be worn in 8 ways
similarly for 2 belts = 2 ways
five pair of jeans= 5 ways
so total number of ways=5*2*8=80 ways
You might be interested in
Answer:
C
Step-by-step explanation:
The answer is 392.3 in standard form
Answer:
![-2m^2-mn-2m+5n+4n^2](https://tex.z-dn.net/?f=-2m%5E2-mn-2m%2B5n%2B4n%5E2)
Step-by-step explanation:
![-2m(m+n-4)+5(-2m+2n)+n(m+4n-5)\\=-2m^2-2mn+8m-10m+10n+mn+4n^2-5n\\=-2m^2-2mn+mn+8m-10m+10n-5n+4n^2\\=-2m^2-mn-2m+5n+4n^2\\](https://tex.z-dn.net/?f=-2m%28m%2Bn-4%29%2B5%28-2m%2B2n%29%2Bn%28m%2B4n-5%29%5C%5C%3D-2m%5E2-2mn%2B8m-10m%2B10n%2Bmn%2B4n%5E2-5n%5C%5C%3D-2m%5E2-2mn%2Bmn%2B8m-10m%2B10n-5n%2B4n%5E2%5C%5C%3D-2m%5E2-mn-2m%2B5n%2B4n%5E2%5C%5C)
Answer:
55.56%
Step-by-step explanation:
Remember, x^-1=1/x
so
f(-1)=4(7)^-1=4(1/7)=4/7
f(2)=4(7)^2=4(49)=196