9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
1hour=60min
24hour=?
24hour=1440 min
1d=1440 min
4.8d=?
4.8 days =6956 hope you like my explanation
The correct answer is y= 0.513(1.833)^x
Explain
We will use the equation on this form
Y=ab^x
Let’s us plug in the coordinates of first point
(X, y) , ( 9, 120)
We will have
Y=ab^x
120= ab^9
Our equation for a will be
Ab^9 = 120
ab ^9 / b^9 = 120/ b^9
a = 120/ b^9
So will have
Y= 120/ b^9 • b^x
Then we will plug in coordinates for the second point
( x,y) = ( 10, 220)
We will have
Y= 120/b^9 • b^x
220 = 120/b^9 • b^10-9
220= 120b
Divide both side by 120
B= 11/6
B= 1.833333 = 1.833
Let’s plug in the value b=11/6 to our equation for a
A= 120/b^9
A= 120/ 11/6^9
A= 120/11^9/6^9
A=120 • 6^9 / 11^9
= 0.51285 which equal to 0.513
So therefore the answer is
Y= 0.513(1.833)^x
I hope this help you
:D
Answer:
5520 min
Step-by-step explanation:
4*115=460
460*12=5520
Answer:
Step-by-step explanation:
an equation perpendicular to the equation given will have a slope of -1, because a perpendicular slope is opposite and reciprical. if it goes through the point 4,-1 and has a slope of -1, the y intercept has to be 3. y = -x + 3
parallel lines have to have the same slope of 3.
