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Margaret [11]
2 years ago
11

The work of a student to find the dimensions of a rectangle of area 8 + 16x and width 4 is shown below:

Mathematics
1 answer:
enyata [817]2 years ago
4 0
Step 3
I think ?
Not sure
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How do you do this question?
velikii [3]

Answer:

∫₂³ √(1 + 64y²) dy

Step-by-step explanation:

∫ₐᵇ f(y) dy is an integral with respect to y, so the limits of integration are going to be the y coordinates.  a = 2 and b = 3.

Arc length ds is:

ds = √(1 + (dy/dx)²) dx

ds = √(1 + (dx/dy)²) dy

Since we want the integral to be in terms of dy, we need to use the second one.

ds = √(1 + (8y)²) dy

ds = √(1 + 64y²) dy

Therefore, the arc length is:

∫₂³ √(1 + 64y²) dy

3 0
3 years ago
Which angle is an exterior angle of the triangle?
Monica [59]

Answer:

What triangle

Step-by-step explanation:

3 0
2 years ago
The difference of a number and 6is the same as 5 times
leva [86]

Answer:

let difference be x

Step-by-step explanation:

you can solve for x by keeping the 2 statesments as conditions.

then you solve for both equations together by adding subtracting or multiplying.

eg: let x be the number.

the. proceed with conditions as equations

then solve

then your answer is here

5 0
1 year ago
Find the volume of a pyramid with a square base, where the perimeter of the base is 10.7\text{ ft}10.7 ft and the height of the
Airida [17]

Answer:

V=23.37\ ft^3

Step-by-step explanation:

Given that,

The perimeter of the base of pyramid, P = 10.7 ft

The height of the pyramid, h = 9.8 ft

We need to find the volume of the pyramid.

The perimeter of square is given by :

4s = 10.7, s is side

s = 2.675 ft

Now the volume of pyramid is given by :

V=\dfrac{lbh}{3}\\\\=\dfrac{2.675^2\times 9.8}{3}\\\\V=23.37\ ft^3

So, the volume of the pyramid is equal to 23.37\ ft^3.

4 0
3 years ago
2x^2 + 3x - 12 when x = 5 help pls
cluponka [151]

\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

\mathsf{= 2(5)^2 + 3(5) - 12}

\mathsf{5^2}

\mathsf{= 5 \times 5}

\mathsf{\bf = 25}

\mathsf{2(25) + 3(5) - 12}

\mathsf{2(25)}

\mathsf{= \bf 50}

\mathsf{3(5)}

\mathsf{= \bf 15}

\mathsf{= 50 + 15 -  12}

\mathsf{50 + 15}

\mathsf{= \bf 65}

65 - 12

\mathsf{= \bf 53}

\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

5 0
2 years ago
Read 2 more answers
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