Answer:
9,490 & 12,880
Step-by-step explanation:
9491 rounded to the nearest 10 would round down to 9490
12876 rounded to the nearest 10 would round up to 12880
Answer:
300 Kilo-meters
Step-by-step explanation:
Since 4 / 5 of a liter runs for 12 kilo-meters and you need to find how much 20 liters would run, you need to find how much a liter can run for.
L is the variable for which how much a liter can run for. Which is what we need to solve.
4 / 5 x L = 12
To isolate L, you need to multiply both sides by 5/4 since multiplying a number by its reciprocal produces one. Note: A reciprocal is a number where the denominator and numerator are switched. Example: 2/3 and 3/2 multiplying it with each other get 6/6 which is 1.
4 / 5 x 5 / 4 x L = 12 x 5 / 4
L = 12 x 5 / 4
L = 60/4
L = 15
Now you know that each liter is worth 15 kilo-meters and you need to find how much 20 liters will run for.
20 x L = Kilo's Ran
20 x 15 = Kilo's Ran
300 = Kilo's Ran
20 Liters will run for 300 Kilo-meters.
I Hope This Helps You :)
Answer:
78.5 square units
Step-by-step explanation:
Answer:
x= 0
Step-by-step explanation:
Let's first simplify the equation to make the PEMDAS process easier.
8x-10=3x-10+7x
8x-10=10x-10
Now lets start the subtracting and dividing process.
8x=10x
0=2x
0=x
Answer:
Variation equation: y = k/√x
constant of variation: 200
Variation Equation by plugging the value of k: y = 200/√x
Step-by-step explanation:
If y varies inversely with the SQUARE ROOT of x, then;
y = k/√x
If x = 4, y = 100.
100 = k/√4
100 = k/2
200 = k
k = 200
Substitute into the expression
y = k/√x
y = 200/√x
