Simplify the following:
((-1^3)/(-3)^(-3))^2
1^3 = 1:
((-1)/(-3)^(-3))^2
(-3)^(-3) = 1/(-1)^3×1/3^3 = (-1)/3^3:
((-1)/((-1)/3^3))^2
3^3 = 3×3^2:
((-1)/(-1/(3×3^2)))^2
3^2 = 9:
((-1)/((-1)/(3×9)))^2
3×9 = 27:
((-1)/((-1)/27))^2
Multiply the numerator of (-1)/((-1)/27) by the reciprocal of the denominator. (-1)/((-1)/27) = (-27)/(-1):
((-27)/(-1))^2
(-27)/(-1) = (-1)/(-1)×27 = 27:
27^2
| 2 | 7
× | 2 | 7
1 | 8 | 9
5 | 4 | 0
7 | 2 | 9:
Answer: 729 = 1/729 thus c: is your Answer
<span> The product of two perfect squares is a perfect square.
Proof of Existence:
Suppose a = 2^2 , b = 3^2 [ We have to show that the product of a and b is a perfect square.] then
c^2 = (a^2) (b^2)
= (2^2) (3^2)
= (4)9
= 36
and 36 is a perfect square of 6. This is to be shown and this completes the proof</span>
Answer:
2,380
Step-by-step explanation:
Answer:
Whats the question
Step-by-step explanation:
Answer:
I'm pretty sure it would be (5,6)
Step-by-step explanation:
Reflecting a point over the Y-axis would change the x-coordinate, but not the y-coordinate
