Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Subtract the amount used from the total packets:
5000 - 1824 = 3176 left after the first week.
3176 - 2352 = 824 total packets left.
25÷100=0.25
0.25×680=170 is the answer
I think the anser is c that what i think
Answer: the future value is $1748.4
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1550
r = 4% = 4/100 = 0.04
n = 365 because it was compounded 365 times in a year.
t = 3 years
Therefore,.
A = 1550(1 + 0.04/365)^365 × 3
A = 1550(1+0.00011)^1095
A = 1550(1.00011)^1095
A = 1550 × 1.128
A = 1748.4
