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kherson [118]
3 years ago
13

WILL MARK BEST ANSWER!! PLEASE HELP On a piece of paper, draw a box plot to represent the data below. Then

Mathematics
1 answer:
zlopas [31]3 years ago
4 0
The answer is A:

Because the only difference between the rest of the answer choices are the lower and upper quartiles, that is all you need to find. In order to do so you find the median for the first half (lower quartile) and then find the median for the second half. In this case it is 29 (Q1) and 58 (Q2)
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Struggling with this question can someone help? 10points
adelina 88 [10]

Answer:Answer is B.


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic
aliya0001 [1]

Answer:

P-value =  0.4846

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4.73

Sample mean, \bar{x} = 4.35

Sample size, n = 51

Alpha, α = 0.05

Sample standard deviation, s = 3.88

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4.73\\H_A: \mu \neq 4.73

We use Two-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{4.35 - 4.73}{\frac{3.88}{\sqrt{51}} } = -0.699

Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

We can calculate the p-value with the help of standard normal table.

P-value =  0.4846

Since the p-value is higher than the significance level, we fail to reject the null hypothesis and accept it.

We conclude that this college has same drinking habit as the college students in general.

7 0
3 years ago
Simplify completely 2x-24 over 8
77julia77 [94]

Answer:

x-12/4


Step-by-step explanation:

hope its correct :-)

8 0
3 years ago
What is the greatest common factor of 63b^2c^4 and 42b^3c^2
Arte-miy333 [17]

Factor out the GCF of  

21

b

2

c

2

from  

63

b

2

c

4

+

42

b

3

c

2

.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from each term in the polynomial.

Tap for fewer steps...

Factor out the GCF of  

21

b

2

c

2

from the expression  

63

b

2

c

4

.

21

b

2

c

2

(

3

c

2

)

+

42

b

3

c

2

Factor out the GCF of  

21

b

2

c

2

from the expression  

42

b

3

c

2

.

21

b

2

c

2

(

3

c

2

)

+

21

b

2

c

2

(

2

b

)

Since all the terms share a common factor of  

21

b

2

c

2

, it can be factored out of each term.

21

b

2

c

2

(

3

c

2

+

2

b

)

The greatest common factor  

GCF

is the term in front of the factored expression.

21

b

2

c

2

6 0
3 years ago
Read 2 more answers
Write the equation of the circle graphed below.
Darina [25.2K]

Answer:

Your equation is (x - 1)^2 + (y +1)^2 = (\frac{1}{2}  )^2

Step-by-step explanation:

Well, the center origin of the circle is given (h,k) =  (1,-1).

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (1,-1) and (x,y) =  (0.5,-1) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

(0.5 - (1))^2 + (-1 - (-1))^2 = r^2

(-0.5)^2 + (0)^2 = r^2

1/4= r^2

r^2 = 1/4

r = 1/2

6 0
1 year ago
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