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satela [25.4K]
3 years ago
6

The base of a right rectangular pyramid has length 14 ​cm, width 12 ​cm, and height 13 cm. Describe a cross section that could b

e formed by a horizontal plane that intersects the faces of the pyramid above the base.
Mathematics
1 answer:
lakkis [162]3 years ago
8 0
It would be a RECTANGLE proportional to the base of the pyramid.
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IgorLugansk [536]
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6 0
3 years ago
two students sit in the first row. in the second, 2 student sit behind each of those students, and so on. how many students sit
ankoles [38]
I think its 2 bc two ppl sit behind each persin from the first and second row.
3 0
3 years ago
X-3 and 2x-1 are factors of 2x^3-px^2-2qx+q. Find the values of p and q.
Nonamiya [84]

Answer:

p =1

q = 9

Step-by-step explanation:

f(x) = 2x³ - px² + 2qx + q

(x - 3) is a factor of f(x)

⇒f(3)  = 0

2(3)³ - p*3² - 2q*3 +q = 0

2*27 - 9p - 6q + q = 0

    54 - 9p - 5q = 0

            -9p - 5q = -54 -------------------(I)

(2x - 1) is a factor of f(x)

2x - 1 = 0

      2x = 1

        \st x = \dfrac{1}{2}

f(1/2) = 0

2*(\dfrac{1}{2})^{3}-p*(\dfrac{1}{2})^{2}-2q*\dfrac{1}{2}+q=0\\\\2*\dfrac{1}{8}-p*\dfrac{1}{4}-q+q = 0\\\\\dfrac{1}{4}-\dfrac{1}{4}p =0\\\\[Multiply the entire equation by 4]\\\\4*\dfrac{1}{4}-4*\dfrac{1}{4}p=0\\\\

1 - p = 0

    -p = -1

p = 1

Substitute p =1 in equation (I)

-9*1 - 5q = -54

 -9 - 5q = -54

      -5q = -54 + 9

      -5q = -45

           q = -45/(-5)

q = 9

8 0
3 years ago
The average height of 8 adults is 1.8 m. What is the sum of their heights? How do I work this out without a calculator?
Katen [24]
Well, the average of a sum of number is found by adding each given number and dividing that number by the amount of given numbers. 
Example: 5+4+3+8=20 
                and 20/4 = 5, the average of the numbers
Multiply 1.8 by 8.0 using this format:

1.8
x8.0
--------


Hope this helped
5 0
3 years ago
Given ABC find the values of x and y. In your final answer, include all of your calculations.
kow [346]

So with this, we will be using proportions. To solve for x, our proportion will be \frac{x}{6} =\frac{6}{x-9}


Firstly, cross-multiply: x^2-9x=36


Next, subtract 36 on both sides: x^2-9x-36=0


Next, replace -9x with 3x-12x x^2+3x-12x-36=0


Next, factor x^2+3x and -12x-36 separately: x(x+3)-12(x+3)=0 . After, rewrite it as (x-12)(x+3)=0


Next, solve for x separately in the two parentheses:

x-12=0\\ x=12

x+3=0\\ x=-3


Since we can't have a negative length, x = 12.



To solve for y, our proportion will be \frac{y}{9} =\frac{12}{y}


Firstly, cross-multiply: y^2=108


Next, just square root each side, and your answer will be (rounded to hundredths) y=10.39



In short, x = 12 and y = 10.39.

5 0
3 years ago
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