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3 years ago

Please help!!! I’m on functions Khan. Will give Brainliest

Mathematics

2 answers:

SashulF [63]3 years ago

5 0

It’s 20f-30g I just took that question on a test

Dennis_Churaev [7]3 years ago

3 0

f(6) means that you look at x = 6 and notice the y-axis, then you will get the answer.

If you don't know. f(6) = -6 (Look at x = 6 then look at y = -6.)

Also for g(5), same with f(6). Look at x = 5 and notice the y-axis. When x = 5, y = -5.

Now we know that f(6) = -6 and g(5) = -5

Substitute f(6) = -6 and g(5) = -5 for easier look.

$-6-6*(-5) = -6+30 = 24$

So the answer is 24.

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2. George is buying orange juice for a class party, he expects that 26 people will be attending and that each person will drink

Agata [3.3K]

Answer: He needs 364 ounces.

Step-by-step explanation:

26 * 1.75 = 45.5

1 cup = 8 ounces

5 0

2 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Please help out thanks :)

Mkey [24]

The correct answer is D The last one

Step by step is below

Hopefully this help you

Have a great day :)

3 0

3 years ago

I need help ASAP ???

kondor19780726 [428]

Answer:

He said he accidentally sent this so I just want everyone who reads this to have a good rest of their day:)

Step-by-step explanation:

5 0

2 years ago

Each student at State College has a student ID number consisting of four digits followed by three of the letters A, B, C, D, and

yarga [219]

The Many different student numbers are five

3 0

3 years ago