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4 years ago

Mathematics help please

Mathematics

1 answer:

Andrews [41]4 years ago

7 0

2. (-1-2^2•5)3^2

= -4509

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According to a human modeling project, the distribution of foot lengths of women is approximately Normal with a mean of 23.4 ce

stiv31 [10]

Answer: 22.0.6%

Step-by-step explanation:

Given : According to a human modeling project, the distribution of foot lengths of women is approximately Normal with $\mu=23.3\ cm$ and $\sigma=1.3\ cm$ .

In the United States, a woman's shoe size of 6 fits feet that are 22.4 centimeters long.

Then, the probability that women in the United States will wear a size 6 or smaller :-

$P(x\leq22.4)=P(z\leq\dfrac{22.4-23.4}{1.3})\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\\approx P(z\leq-0.77)\\\\=1-P(z\leq0.77)\\\\=1-0.77935=0.2206499\approx0.2206=22.06\%$

Hence, the required answer = 22.0.6%

4 0

3 years ago

Please please help me it's for my homework

serg [7]

Answer:

6/25

Step-by-step explanation:

.24 = 24/100 = 6/25

3 0

3 years ago

Read 2 more answers

What is 9+10 in mathematics

MrRa [10]

Answer: 21

Step-by-step explanation:

6 0

3 years ago

(sinx-1)(sinx+cos^2x) multiply and simplify

sveta [45]

$\bf [sin(x)-1][sin(x)+cos^2(x)]\\\\
-------------------------------\\\\
sin^2(x)+sin(x)cos^2(x)-sin(x)-cos^2(x)
\\\\\\\
[sin^2(x)-cos^2(x)]+[sin(x)cos^2(x)-sin(x)]
\\\\\\
-[cos^2(x)-sin^2(x)]-[sin(x)-sin(x)cos^2(x)]
\\\\\\
-[\stackrel{cos(2x)}{cos^2(x)-sin^2(x)}]-sin(x)\stackrel{sin^2(x)}{[1-cos^2(x)]}
\\\\\\
-cos(2x)-sin(x)sin^2(x)\implies -cos(2x)-sin^3(x)$

7 0

3 years ago

The 18th term of an arithmetic sequence is 49 and the first term is 15.

Tju [1.3M]

Answer:

Step-by-step explanation:

49-15=34

34/17=2

For this sequence, you can write this function:

f(x)=15+2(x-1)

Check:

f(18)=15+2(18-1)

f(18)=15+2(17)

f(18)=15+34

f(18)=49

So:

f(10)=15+2(10-1)

f(10)=15+2(9)

f(10)=15+18

f(10)=33

5 0

3 years ago