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Contact [7]
4 years ago
10

Rick has a collection of 6 video games he lets his friend borrow 2/6 of his video games collection write two fractions equivalen

t to this number explain how you came up with fractions
Mathematics
1 answer:
rosijanka [135]4 years ago
5 0
4/12 and 6/18 because all the fractions (2/6,4/12, and 6/18) reduce down to 1/4.
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How do i rename 2/7 and 10/21 and whats the most common denominator for them
emmainna [20.7K]

Answer:

just multiply 7 by 21 and 21 by 7

like

2*21/7*21. + 10*7/21*7

41/147+ 70/147

111/147. Ans

6 0
3 years ago
Read 2 more answers
The glee club needs to raise money for the spring trip to Europe, so the members are assembling holiday wreaths to sell. Before
Ksju [112]

Answer:

5 pinecones on the deluxe wreath and 4 pinecones on the regular wreath

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
In the xy-plane, point E has coordinates (4,5) and point O has coordinates (0,0). Which of the following is an equation of the l
Paha777 [63]

Answer:

D

Step-by-step explanation:

You can plug in the given x and y values into the equations and see which one works for both of them.

D works for both of them:

5 = 5/4(4)

0 = 5/4(0)

6 0
4 years ago
A recent study in a small city stated that the average age of robbery victims was 63.5 years. A random sample of 20 recent victi
Elina [12.6K]

Answer:

The p-value of the test is of 0.3219 > 0.05, which means that at \alpha = 0.05, the average age is not higher than originally believed.

Step-by-step explanation:

A recent study in a small city stated that the average age of robbery victims was 63.5 years. Test if the average age higher than originally believed.

At the null hypothesis, we test that the mean is the believed mean age of 63.5 years, that is:

H_0: \mu = 63.5

At the alternate hypothesis, we test if this mean is higher, that is:

H_1: \mu > 63.5

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

63.5 is tested at the null hypothesis:

This means that \mu = 63.5

A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years.

This means that n = 20, X = 63.7, s = 1.9

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{63.7 - 63.5}{\frac{1.9}{\sqrt{20}}}

t = 0.47

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 63.7, which is a right-tailed test, with t = 0.47 and 20 - 1 = 19 degrees of freedom.

With the help of a calculator, this probability is of 0.3219.

The p-value of the test is of 0.3219 > 0.05, which means that at \alpha = 0.05, the average age is not higher than originally believed.

5 0
3 years ago
the profit p in dollars from selling x calculators is p=25x-(10x+250) how many calculators are sold when the profit is $425
podryga [215]
425=25x-10x-250
675=15x
x=45
45 calculators were sold.

4 0
3 years ago
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