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2 years ago

What is the volume of the circle?

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

4 0

Answer:

Multiply the circle's area by the cylinder's length to obtain the volume. If the length is, for instance, 10 inches, then compute as follows: 113 x 10 = 1,130 cubic inches.

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)) Evaluate the expression for b = 7.<br> 11b - 75 =

Wewaii [24]

Answer:

The answer is 2.

Step-by-step explanation:

11(7) - 75

77-75

7 0

3 years ago

Find the number of primes less than 190 using the principle of inclusion-exclusion.

Troyanec [42]

The number of primes less than 190 using the principle of inclusion-exclusion are 42

<h3>Principle of inclusion- exclusion</h3>

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

Learn more about prime numbers here:

brainly.com/question/874965

#SPJ11

8 0

2 years ago

m hits a baseball 4 times as often as t each game he also hits 20 baseballs every monday at practice. how many baseballs will m

baherus [9]

M will hit 16 baseballs (4x4=16)

7 0

3 years ago

Read 2 more answers

A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent

Yuri [45]

the yearly increase of x% assumes is compounding yearly, so let's use that.

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\£95000\\ P=\textit{original amount deposited}\dotfill &\£80000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}$

$95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r$

4 0

2 years ago

Examine the graph of the logarithmic function f(x).

Eduardwww [97]

Answer:

The function f(x) has a vertical asymptote at x = 3

Step-by-step explanation:

We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.

For example, in the case of the natural logarithm, it is not defined for x = 0.

Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)

So a vertical asymptote will be a vertical tendency at a given x-value.

In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)

Then:

The function f(x) has a vertical asymptote at x = 3

6 0

3 years ago