Answer:


Step-by-step explanation:
El cos(α) se define como el cociente entre el cateto adyacente y la hipotenusa.
El valor del cateto adyacente en nuestgro caso es CA = 3.
La hipotenusa se calcual de la siguiente manera:

Por lo tanto, el cos(α) sera:

El cosec(α)=h/CO.
El cateto opuesto CO = 4 y la hipotenusa h = 5
Por lo tanto, el cosec(α) sera:

Espero te haya sido de ayuda!
Answer:
(7,-3)
Step-by-step explanation:
y = -3
substitute in the first equation
3x - y^2 = 12
3x - (-3)^2 = 12
3x - 9 = 12
3x = 12 + 9
3x = 21
x = 7
coordinates of intersection (7,-3)
(6,(31pi/180)+2 n pi)
(-6,(31pi/180)+2 n pi)
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Answer:
Step-by-step explanation:
<u>Pool:</u>
Width = x ft
Length = (x+6) ft
<u>Pool along with walkway:</u>
Width = x + 5 + 5 = (x + 10) ft
Length = x + 6 + 5 + 5 = (x + 16) ft
Total area of the pool with walkway = 950 sq.ft
length * width = 950
(x+16) * (x + 10) = 950
Use FOIL method,
x*x + x *10 + 16*x + 16 *10 = 950
x² + 10x + 16x + 160 -950 = 0 {Add like terms}
x² + 26x - 790 = 0
Here r ur terms : (9x^2) , (-5x) , (-7)......so there r 3 terms
constant : a number by itself...no variables....so ur constant is -7