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Rufina [12.5K]
3 years ago
9

Will give brainiest

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

Answer:

23/24 miles

Step-by-step explanation:

You have to simplify the fractions to like terms

The <u>lowest</u> common number that 3 and 8 have in common is 24

1 x 8 = 8

3 x 8 = 24

This makes <u>8/24 </u>

5 x 3 = 15

8 x 3 = 24

This makes <u>15/24</u>

Now you can add 8/24 and 15/24

8 + 15 = 23

<u>Because it is a common denominator, we do not add it, which makes 23/24</u>

Now you simplify as much as possible (if possible)

Because 23 is not divisable by any other number, 23/24 is the simpliest form

lubasha [3.4K]3 years ago
3 0

Greetings! Hope this helps!

Answer

7/24 of a mile.

Explanation

5/8 1/3, Find common demoninator

15/24 8/24, Subtract

7/24 simplify

Have a good day!

_______________

A brainliest would help tons! :D

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tatuchka [14]

Hey there! I was looking at your question for a bit then realized you meant i, the imaginary number, not "1" at the end of each number.

  • Complex numbers are numbers involving both real and imaginary numbers; thus, this question wouldn't make much sense without the imaginary number i

The expression we are given is:

(3+4i)+(8+2i)

Open parenthesis and combine like terms:

=3+4i+8+2i

=11+6i

This is answer choice B (assuming it's supposed to be an i and not a "1" at the end)

Let me know if you need any clarifications, thanks!

~ Padoru

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The distance between the two points (4,1) and (9,1) is​
Rzqust [24]

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6 0
3 years ago
Which answer choice shows 21.97 written in expanded form? A. 2 + 1 + 9 + 7 B. 20 + 1 + 0.9 + 0.7 C. 20 + 10 + 0.9 + 0.07 D. 20 +
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Answer:

20 + 1 + 0.9 + 0.07

Step-by-step explanation:

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
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