Question

Plz help me to solve this question

Answer 1

Answer:

a = 18°

$b= 108\degree$

Step-by-step explanation:

ABCD is a rhombus.

AC and BD are its diagonals

Diagonals of a rhombus bisects at right angles.

Therefore,

5a = 90°

a = 90°/5

a = 18°

2a = 2*18° = 36°

Diagonals of a rhombus bisects the opposite angles.

Therefore,

$m\angle ADC = 2(2a)$

$m\angle ADC = 2\times 36\degree$

$m\angle ADC = 72\degree$

$m\angle ADC+m\angle DCB= 180\degree$

(Adjacent angles of a rhombus are supplementary)

$72\degree+b= 180\degree$

$b= 180\degree-72\degree$

$b= 108\degree$

Answer 2

Step-by-step explanation:

diagonals of the rhombus bisect each other at right angles .

5a = 90

a = 90/5 = 18

in ∆ OCD:

5a + 2a + b = 180

7a+ b = 180

b = 180 - 7 ( 18)

b = 180 - 126

b = 54 °

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