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Hatshy [7]
3 years ago
13

2. The following are representative particles of matter: which among them

Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0
Huyahehdhdhhdyyrhhr. Hey how did I miss the day how are ya mungu is that app that you have a gd
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Calculate the grams of C6H6 needed to produce 25 g of CO2<br> Show your work
Anna007 [38]

Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

M

M

C

O

2

=

44.01

g

/

m

o

l

M

M

C

6

H

6

=

78.11

g

/

m

o

l

and their mole ratio:

12

m

o

l

C

O

2

2

m

o

l

C

6

H

6

→

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

.

it is a problem of app

3 0
3 years ago
When baking soda and vinegar react, the product includes bubbles. what is most likely occurred
Varvara68 [4.7K]
The gases that get released form bubbles in the solution
4 0
3 years ago
Read 2 more answers
Can someone plz help me with this plz?????
Otrada [13]

Answer:

We can't see the options so we don't know what we can put

Explanation:

4 0
3 years ago
How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)
11Alexandr11 [23.1K]

98.56 dm^3 of oxygen at STP would be required to react completely with 38.8g of propane.

<u>Given that :</u>

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = \frac{38.8}{44} = 0.88 mole

<u>applying rule of balanced equations </u>

1 mole of propane = 5 moles of oxygen

0.88 mole of propane =  5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = 22.4 dm^3

∴Total volume of oxygen required at STP = 22.4 * 4.4 = 98.56 dm^3

Hence we can conclude that the volume of oxygen at STP required to react completely 98.56 dm^3

Learn more : brainly.com/question/16998374

5 0
2 years ago
In the reaction N2O4(g) 2NO2(g), what changes in color would you expect as pressure is increased at constant temperature?
skelet666 [1.2K]

Answer:

Brown color of the solution decreases

Explanation:

NO_2 is brown in color whereas N_2O_4 is colorless.

Equilibrium reaction between NO_2 and N_2O_4 is as follows:

2NO_2\leftrightharpoons N_2O_4

As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.

In the given equilibrium, NO_2 side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of N_2O_4 or more formation of N_2O_4 will take place.

Therefore, more NO_2 will decompose that will decrease the brown color of the solution as N_2O_4 is colorless.

6 0
3 years ago
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