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stiks02 [169]
3 years ago
11

HURRY PLEASE (MULTI CHOICE)

Chemistry
2 answers:
Mama L [17]3 years ago
6 0
The magnets in a maglev train system help move, or propel, the train
Lera25 [3.4K]3 years ago
5 0

Answer:

maglev

Explanation:

<em>In</em><em> </em><em>a</em><em> </em><em>train</em><em> </em><em>system</em><em> </em><em>two</em><em> </em><em>magnets</em><em> </em><em>are</em><em> </em><em>present</em><em>:</em><em>one</em><em> </em><em>set</em><em> </em><em>to</em><em> </em><em>repel</em><em> </em><em>and</em><em> </em><em>push</em><em> </em><em>the</em><em> </em><em>train</em><em> </em><em>up</em><em> </em><em>off</em><em> </em><em>the</em><em> </em><em>track</em><em>,</em><em>and</em><em> </em><em>another</em><em> </em><em>set</em><em> </em><em>the</em><em> </em><em>elevated</em><em> </em><em>train</em><em> </em><em>ahead</em><em>,</em><em>taking</em><em> </em><em>advantage</em><em> </em><em>of</em><em> </em><em> </em><em>the</em><em> </em><em>lack</em><em> </em><em>of</em><em> </em><em>friction</em><em>.</em>

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A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature
Doss [256]

Answer:

d i took the test

Explanation:

5 0
3 years ago
How many neutrons would an atom of fluorine have?
lord [1]

Answer:

9

Explanation:

6 0
3 years ago
Read 2 more answers
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

7 0
3 years ago
Consider this reaction 2Mg(s)+O2(g) ———&gt; 2MgO(s) What volume (in milliners) of gas is required to react with 4.03 g Mg at STP
nydimaria [60]

The volume of a gas that is required  yo react with 4.03 g mg  at STP  is 1856 ml



calculation/

  • calculate the moles of Mg used

     moles=mass/molar mass

moles of Mg is therefore=4.03 g/  24.3 g/mol=0.1658  moles

  • by use of mole ratio of Mg:O2  from  the equation  which is 2:1

  the moles 02=0.1679 x1/20.0829 moles

  • at STP  1 mole of a gas= 22.4  l

                            0.0895 moles=? L

  • by cross multiplication
  • =0.0895 moles  x22.4 l/  1 mole=1.8570 L

into Ml = 1.8570 x1000=1856  ml  approximately to 1860

6 0
3 years ago
Is always
Studentka2010 [4]

Answer:

o atom, smaller, anion is the right answer of the following

7 0
3 years ago
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