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Ann [662]
3 years ago
12

Question 7 of 10

Mathematics
2 answers:
dexar [7]3 years ago
3 0

Answer:

I would believe the diameter would be B, if not A

Step-by-step explanation:

Inga [223]3 years ago
3 0

Answer:

the answer for this problem should be 120,536

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The transformation is rotation.
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171

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8m^3 + 2m^3 + 49m^2 .
zimovet [89]

Answer:

m^2(10m+49)

Step-by-step explanation:

Given \ \ 8m^3+2m^3+49m^2\\\\=m^3(8+2)+49m^2 \ \ \ \ \ \ \ (adding\ like\ terms)\\\\=10m^3+49m^2\\\\=10m\times m^2+49m^2\\\\=m^2(10m+49)

3 0
3 years ago
For the straight line defined by the points (3,57) and (5,87), determine the slope ( m ) and y-intercept ( ???? ). Do not round
Sphinxa [80]

Answer: The slope of the line is 15 and y-intercept is 12.

Step-by-step explanation:  We are given to find the slope and y-intercept of the straight line defined by the points (3, 57) and (5, 87).

We know that

the slope of a line passing through the points (3, 57) and (5, 87) is given by

m=\dfrac{87-57}{5-3}=\dfrac{30}{2}=15.

Since the straight line passes through the point (3, 57), so its equation will be

y-57=m(x-3)\\\\\Rightarrow y-57=15(x-3)\\\\\Rightarrow y-57=15x-45\\\\\Rightarrow y=15x-45+57\\\\\Rightarrow y=15x+12.

So, the required equation of the straight line is y=15x+12.

Thus, the slope of the line is 15 and y-intercept is 12.

4 0
3 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
Umnica [9.8K]
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)

We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
7 0
3 years ago
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