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Ierofanga [76]
2 years ago
10

97 inches = how many yards?

Mathematics
1 answer:
PIT_PIT [208]2 years ago
3 0

Answer:

8 yards

Step-by-step explanation:

97 divided by 12

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FromTheMoon [43]

Answer:

v ~ 32.72

Hope that helps!

8 0
3 years ago
Greg feeds his dog 2/3 pounds of dog food for each meal. Greg has just bought 18 pounds of dog food. For how many meals will the
yan [13]
We can divide 18 pounds by 2/3 pounds to find how many servings of meals the dogs will have.
We will use the keep change flip rule to solve this.
18 / 2/3 is then the same as 18 x 3/2
We then multiply across to get
54/2
This would be 27 meals that the food will last
3 0
3 years ago
What is meant by measure of center"?Please define using your own words,or by providing an example.
stepladder [879]

Center:

Center is a point in space, which is at equal distance from all the others points in that space.

5 0
1 year ago
Carlos wrote three numbers between 0.33 and 0.34. What numbers could he have written?
kiruha [24]
There is an infinite number of numbers between 0.33 and 0.34
for example, 0.331, 0.332, 0.3321213323, 0.3333333, 0.3336778, etc.
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5 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
3 years ago
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