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Ierofanga [76]
3 years ago
10

97 inches = how many yards?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0

Answer:

8 yards

Step-by-step explanation:

97 divided by 12

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notsponge [240]
3/18=1/6 and 2/12=1/6
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during a bike challenge, riders have to collect various colored ribbons. each 1/2 mile they collect a red ribbon, each 1/8 mile
Natali [406]
<span><u><em>The correct answer is: </em></u>
green and blue.

<u><em>Explanation</em></u><span><u><em>: </em></u>
We want to see which fractions </span></span>\frac{3}{4} is a multiple of. We know that \frac{3}{4} is a multiple of \frac{1}{4}, because \frac{1}{4}*3=\frac{3}{4}.

We can divide fractions to determine if \frac{3}{4} is a multiple of \frac{1}{2}:
\frac{ \frac{3}{4}}{ \frac{1}{2}};

in order to divide fractions, flip the second one and multiply:
\frac{3}{4})*\frac{2}{1}=\frac{6}{4}=1 \frac{1}{2}.
This did not divide evenly, so \frac{3}{4} is not a multiple of 1/2.

Checking to see if \frac{3}{4} is a multiple of \frac{1}{8}, \frac{ \frac{3}{4}}{ \frac{1}{8}};

flip the second one and multiply:
\frac{3}{4}*\frac{8}{1}=\frac{24}{4}=6.
This divided evenly, so \frac{3}{4} is a multiple of \frac{1}{8}.
6 0
4 years ago
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Tryna pass these midterms​ help me please
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Answer:

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Step-by-step explanation:

7 pounds to 15 dollars is equal to 3 pounds to X dollars

5 0
3 years ago
15,30, 60,... Find the 6th term.​
kolbaska11 [484]

Answer:

15, 30, 60, 120, 240, <u>480</u>.

Step-by-step explanation:

You multiply the numbers by 2 to get to the next number.

For example, 15*2 is 30. 30*2 is 60. 60*2 is 120, etc..

7 0
3 years ago
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If A(4 -6) B(3 -2) and C (5 2) are the vertices of a triangle ABC fine the length of the median AD from A to BC. Also verify tha
Gnoma [55]

Answer:

a) The median AD from A to BC has a length of 6.

b) Areas of triangles ABD and ACD are the same.

Step-by-step explanation:

a) A median is a line that begin in a vertix and end at a midpoint of a side opposite to vertix. As first step the location of the point is determined:

D (x,y) = \left(\frac{x_{B}+x_{C}}{2},\frac{y_{B}+y_{C}}{2}  \right)

D(x,y) = \left(\frac{3 + 5}{2},\frac{-2 + 2}{2}  \right)

D(x,y) = (4,0)

The length of the median AD is calculated by the Pythagorean Theorem:

AD = \sqrt{(x_{D}-x_{A})^{2}+ (y_{D}-y_{A})^{2}}

AD = \sqrt{(4-4)^{2}+[0-(-6)]^{2}}

AD = 6

The median AD from A to BC has a length of 6.

b) In order to compare both areas, all lengths must be found with the help of Pythagorean Theorem:

AB = \sqrt{(x_{B}-x_{A})^{2}+ (y_{B}-y_{A})^{2}}

AB = \sqrt{(3-4)^{2}+[-2-(-6)]^{2}}

AB \approx 4.123

AC = \sqrt{(x_{C}-x_{A})^{2}+ (y_{C}-y_{A})^{2}}

AC = \sqrt{(5-4)^{2}+[2-(-6)]^{2}}

AC \approx 4.123

BC = \sqrt{(x_{C}-x_{B})^{2}+ (y_{C}-y_{B})^{2}}

BC = \sqrt{(5-3)^{2}+[2-(-2)]^{2}}

BC \approx 4.472

BD = CD = \frac{1}{2}\cdot BC (by the definition of median)

BD = CD = \frac{1}{2} \cdot (4.472)

BD = CD = 2.236

AD = 6

The area of any triangle can be calculated in terms of their side length. Now, equations to determine the areas of triangles ABD and ACD are described below:

A_{ABD} = \sqrt{s_{ABD}\cdot (s_{ABD}-AB)\cdot (s_{ABD}-BD)\cdot (s_{ABD}-AD)}, where s_{ABD} = \frac{AB+BD+AD}{2}

A_{ACD} = \sqrt{s_{ACD}\cdot (s_{ACD}-AC)\cdot (s_{ACD}-CD)\cdot (s_{ACD}-AD)}, where s_{ACD} = \frac{AC+CD+AD}{2}

Finally,

s_{ABD} = \frac{4.123+2.236+6}{2}

s_{ABD} = 6.180

A_{ABD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}

A_{ABD} \approx 3.004

s_{ACD} = \frac{4.123+2.236+6}{2}

s_{ACD} = 6.180

A_{ACD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}

A_{ACD} \approx 3.004

Therefore, areas of triangles ABD and ACD are the same.

4 0
4 years ago
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