<span>
<u><em>The correct answer is: </em></u>green and blue.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>We want to see which fractions </span></span>

is a multiple of. We know that

is a multiple of

, because

*3=

.
We can divide fractions to determine if

is a multiple of

:

;
in order to divide fractions, flip the second one and multiply:

)*

=

=1

.
This did not divide evenly, so

is not a multiple of 1/2.
Checking to see if

is a multiple of

,

;
flip the second one and multiply:

*

=

=6.
This divided evenly, so

is a multiple of

.
Answer:
D
Step-by-step explanation:
7 pounds to 15 dollars is equal to 3 pounds to X dollars
Answer:
15, 30, 60, 120, 240, <u>480</u>.
Step-by-step explanation:
You multiply the numbers by 2 to get to the next number.
For example, 15*2 is 30. 30*2 is 60. 60*2 is 120, etc..
Answer:
a) The median AD from A to BC has a length of 6.
b) Areas of triangles ABD and ACD are the same.
Step-by-step explanation:
a) A median is a line that begin in a vertix and end at a midpoint of a side opposite to vertix. As first step the location of the point is determined:



The length of the median AD is calculated by the Pythagorean Theorem:

![AD = \sqrt{(4-4)^{2}+[0-(-6)]^{2}}](https://tex.z-dn.net/?f=AD%20%3D%20%5Csqrt%7B%284-4%29%5E%7B2%7D%2B%5B0-%28-6%29%5D%5E%7B2%7D%7D)

The median AD from A to BC has a length of 6.
b) In order to compare both areas, all lengths must be found with the help of Pythagorean Theorem:

![AB = \sqrt{(3-4)^{2}+[-2-(-6)]^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%283-4%29%5E%7B2%7D%2B%5B-2-%28-6%29%5D%5E%7B2%7D%7D)


![AC = \sqrt{(5-4)^{2}+[2-(-6)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%285-4%29%5E%7B2%7D%2B%5B2-%28-6%29%5D%5E%7B2%7D%7D)


![BC = \sqrt{(5-3)^{2}+[2-(-2)]^{2}}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%285-3%29%5E%7B2%7D%2B%5B2-%28-2%29%5D%5E%7B2%7D%7D)

(by the definition of median)



The area of any triangle can be calculated in terms of their side length. Now, equations to determine the areas of triangles ABD and ACD are described below:
, where 
, where 
Finally,








Therefore, areas of triangles ABD and ACD are the same.