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olganol [36]
3 years ago
6

Arthur is organising his collection of DVDs .He has 36 altogether. The ratio of comedy films to action to horror is 4:8: 1 How m

any of each type of DVD does he have?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer: Because of the total number of DVDs given (36)the number of  individual type of DVD are coming in decimals such that

Number of comedy films =11.07

Number of Action films =22.15

and Number of horror  films =2.78

I also solved using total number of DVDs as 26 and the results were as follows

Number of comedy films =8

Number of acton films =16

and Number of horror  films =2

Step-by-step explanation:

Total number of DVD collection = 36

ratio of the type of DVD =comedy films to action to horror = 4:8: 1

Total ratio =4+8+1 = 13

Number of comedy films = ratio of comedy films/ total ratio x Total DVD collection

= 4/13 x 36= 11,.07 rounded to 11 comedy films

Number of action films = ratio of action films/ total ratio x Total DVD collection

= 8/13 x 36= 22.15 rounded to 22 action films

Number of horror films = ratio of horror films/ total ratio x Total DVD collection

1/13 x 36=2.78 rounded t0 3 Horror movies .

The numbers of each DVD are giving decimal numbers .

Using

Total number of DVD collection  as 26.

we have that

Number of comedy films= 4/13 x 26 = 8

Number of action films= 8/13 x 26= 16

Number of Horror films = 1/13 x 26 = 2

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Answer:

The height of the water = 6.2 in. to the nearest tenth

Step-by-step explanation:

∵ The rate of flows of water into the tank = 8000 in.³/min.

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3 years ago
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In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinate
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Answer:

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If we called:

x = children who have been vacinated against rubella only

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A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de
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Answer:

\frac{23}{4} feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 \frac{1}{2} feet

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The depth of the fish to its initial position at 4:00 pm = 3 \frac{1}{4} feet

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The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

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The position of the fish with respect to the water's surface at 4:00 pm is \frac{23}{4} feet.

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3 years ago
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