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natka813 [3]
2 years ago
12

Suppose that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $500, $250, and $100. How ma

ny distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class
Mathematics
1 answer:
Rudik [331]2 years ago
7 0

Answer:

80 distributions of the three scholarship are possible.

Step-by-step explanation:

Given that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $ 500, $ 250, and $ 100, to determine how many distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class you must perform the following calculation:

4 x 5 x 4 = X

20 x 4 = X

80 = X

Therefore, 80 distributions of the three scholarship are possible.

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g100num [7]

I got 1:4

What I did was added all the catfish samples which was 15. Then I added all the samples together and got 60. I then put them in the ratio and simplified them.

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1:4

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Work out the value of 10/4
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I think the answer to your question is 5/2

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3 years ago
How do you know a radical expression is in simplest form?
Diano4ka-milaya [45]
Answer: To know whether a radical expression is in simplest form or not you should put the numbers and letters inside the radical in terms of prime factors. Then, the radical expression is in the simplest form if all the numbers and letters inside the radical are prime factors with a power less than the index of the radical

Explanation:

Any prime factor raised to a power greater than the index of the root can be simplified and any factor raised to a power less than the index of the root cannot be simplified

For example simplify the following radical in its simplest form:


\sqrt[5]{3645 a^8b^7c^3}

1) Factor 3645 in its prime factors: 3645 = 3^6 * 5

2) Since the powr of 3 is 6, and  6 can be divided by the index of the root, 5, you can simplify in this way:

- 6 ÷ 5 = 1 with reminder 1, so 3^1 leaves the radical and 3^1 stays in the radical

3) since the factor 5 has power 1 it can not leave the radical

4) the power of a is 8, then:

8 ÷ 5 = 1 with reminder 3 => a^1 leaves the radical and a^3 stays inside the radical.

5) the power of b is 7, then:

7 ÷ 5 = 1 with reminder 2 => b^1 leaves the radical and b^2 stays inside the radical

6) the power of c is 3. Since 3 is less than 5 (the index of the radical) c^3 stays inside the radical.

7) the expression simplified to its simplest form is

3ab \sqrt[5]{3.5.a^3b^2c^3}

And you know it cannot be further simplified because all the numbers and letters inside the radical are prime factors with a power less than the index of the radical.
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