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natka813 [3]
2 years ago
12

Suppose that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $500, $250, and $100. How ma

ny distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class
Mathematics
1 answer:
Rudik [331]2 years ago
7 0

Answer:

80 distributions of the three scholarship are possible.

Step-by-step explanation:

Given that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $ 500, $ 250, and $ 100, to determine how many distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class you must perform the following calculation:

4 x 5 x 4 = X

20 x 4 = X

80 = X

Therefore, 80 distributions of the three scholarship are possible.

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A side of a square is 10 cm longer than the side of an equilateral triangle. The perimeter of the square is 3 times the perimete
bija089 [108]

Here's the solution :

  • Side of the equilateral triangle = x

  • Side of square = x + 10

perimeter of equilateral triangle = 3 × x = 3x

perimeter of square = 4 × (x + 10)

now, according to above statement :

permission (square) = 3 × perimeter (triangle)

that is :

  • 4(x + 10)  = 3 \times 3x

  • 4x + 40 = 9x

  • 9x - 4x = 40

  • 5x = 40

  • x = 8

therefore, side of triangle = 8 cm

  • perimeter (triangle) = 8 × 3 = 24 cm

  • side of square = 8 + 10 = 18 cm

  • perimeter of square= 18 × 4 = 72 xm
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2 years ago
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My last one got deleted but whats 10x5 i dont actually but u get it
andre [41]

Answer:

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Step-by-step explanation:

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3 years ago
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What is the value of x?
QveST [7]

Answer:

72°

Explanation:

Given that line J and line K are parallel, we can safely assume that line m is the transversal for the following question. We can also remove line l so that we can focus on line m instead.

Using the rule of <u>Alternate Exterior Angle</u> theorem, x would equal to 72°.

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F(x)=|3x+5|+6<br> g(x)=7<br> find (f+g) (x).
horrorfan [7]

Answer:

(f+g) (x)=\mid 3x+5\mid+13

Step-by-step explanation:

<u>Operation of Functions</u>

Given:

f(x)=\mid 3x+5\mid+6

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The sum of (f+g) (x) is:

(f+g) (x)=\mid 3x+5\mid+6+7

We cannot operate with the expression inside the absolute bars, thus:

\boxed{(f+g) (x)=\mid 3x+5\mid+13}

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