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natka813 [3]
2 years ago
12

Suppose that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $500, $250, and $100. How ma

ny distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class
Mathematics
1 answer:
Rudik [331]2 years ago
7 0

Answer:

80 distributions of the three scholarship are possible.

Step-by-step explanation:

Given that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $ 500, $ 250, and $ 100, to determine how many distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class you must perform the following calculation:

4 x 5 x 4 = X

20 x 4 = X

80 = X

Therefore, 80 distributions of the three scholarship are possible.

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1) A research team is planning to use an ice drill at the top of a glacier. The team plans to use the drill for 10 hours each da
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Answer:

Answer is 50 trust me

Step-by-step explanation:

7 0
3 years ago
Es There are 30 students on the debate team and 20 students on the math team. Ten students are on both the math team and
irakobra [83]
There will be 40 students!!!
5 0
3 years ago
During a building project, a brick is
taurus [48]

The brick will fall to the ground after 9 secs.

<h3>What are quadratic equations?</h3>

Given the equation for height as a function of time is  h(t) = -16t2 + 1,296

The height of the brick on the ground is h(t) = 0. Substitute h(t) = 0 into the equation as shown:

  • -16t2 + 1,296 = 0

Subtract 1296 from both sides

-16t² + 1,296 - 1296 = 0 - 1296

16t² = 1296

t² = 1296/16

t² = 81

t = 9secs

Hence the brick will fall to the ground after 9 secs.

Learn more on equations here: brainly.com/question/13763238

3 0
2 years ago
Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
2 years ago
Read 2 more answers
A helicopter hovers at an altitude that is 1000 feet above a mountain of altitude 5210 feet. A second, taller peak is viewed fro
ehidna [41]
Given: 

Height of Mountain A = 5210 feet
Distance of Mountain A from a helicopter above the peak = 1000 feet
Angle of depression:
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       Mountain B to Mountain A = 19 degrees
 
 First, draw an illustration and label the enumerated given values.

Observe that there are two right triangles formed:

From the triangle formed by the helicopter and Mountain B, 

let x = total height of mountain B
     y = leg of first triangle (helicopter and mountain b)
     h = hypotenuse
Use the Pythagorean Theorem:

cos (43) = y / h

From the second triangle formed by mountain b and a,

cos (19) = (1000 + y) / h

solve for h and y

then, solve for the height of Mountain B:

x = 1000 + y + 5210
6 0
3 years ago
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