Answer:
Answer is 50 trust me
Step-by-step explanation:
The brick will fall to the ground after 9 secs.
<h3>What are quadratic equations?</h3>
Given the equation for height as a function of time is h(t) = -16t2 + 1,296
The height of the brick on the ground is h(t) = 0. Substitute h(t) = 0 into the equation as shown:
Subtract 1296 from both sides
-16t² + 1,296 - 1296 = 0 - 1296
16t² = 1296
t² = 1296/16
t² = 81
t = 9secs
Hence the brick will fall to the ground after 9 secs.
Learn more on equations here: brainly.com/question/13763238
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Given:
Height of Mountain A = 5210 feet
Distance of Mountain A from a helicopter above the peak = 1000 feet
Angle of depression:
Mountain B to helicopter = 43 degrees
Mountain B to Mountain A = 19 degrees
First, draw an illustration and label the enumerated given values.
Observe that there are two right triangles formed:
From the triangle formed by the helicopter and Mountain B,
let x = total height of mountain B
y = leg of first triangle (helicopter and mountain b)
h = hypotenuse
Use the Pythagorean Theorem:
cos (43) = y / h
From the second triangle formed by mountain b and a,
cos (19) = (1000 + y) / h
solve for h and y
then, solve for the height of Mountain B:
x = 1000 + y + 5210