2[6+4{m-6(7-n-p)+q}] Algebraic expression
2 answers:
You might be interested in
Answer:
We conclude that the population mean is 24.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 24
Sample mean, = 22.8
Sample size, n = 100
Alpha, α = 0.05
Sample standard deviation, s = 8.3
First, we design the null and the alternate hypothesis
We use Two-tailed z test to perform this hypothesis.
Formula:
Putting all the values, we have
We calculate the p-value with the help of standard z table.
P-value = 0.1498
Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.
Now,
Since, the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.
now, notice, the rate of change for downloading is negative, because, "y" is decreasing, namely the Mbs to be downloaded, are less and less and less as the minutes go by, because the file is almost fully downloaded
so is -4.8
now... at 8minutes, there are 9.6Mbs to download
bear in mind that 9.6 is just 4.8 * 2
that simply means, another minute, another 4.8 Mbs, and another minute and another 4.8 Mbs and the file is done
so, the file downloaded really in 10minutes
now, we know the rate is -4.8 or -24/5, let us nevermind the sign for now
since we know the file is downloading at 24Mbs in 5minutes, a rate of 24/5
how much is it for 10 minutes? well 10 is really just 5 * 2
so if it downloads at a rate of 24Mbs per 5mins, in 10 minutes it downloaded 24*2 or 48Mbs