Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.

Answer 1

A(0,0) A'(2,1)
distance(AA') = √(2^2 + 1^2)
= √5
= 2.24

answer
Distance AA' = √5 or = 2.24

Answer 2

Answer with Step-by-step explanation:

As we can see from the graph:

A=(0,0)  and A'=(2,1)

Distance between (x1,y1) and (x2,y2) is given by:

    $\sqrt{{(x1-x2)}^2+{(y1-y2)}^2}$

Here (x1,y1)=(0,0)  and (x2,y2)=(2,1)

Hence, distance between A and A' is:

    $\sqrt{{(0-2)}^2+{(0-1)}^2}$

=   $\sqrt{4+1}$

=   $\sqrt{5}$

Hence, distance AA'=√5