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Archy [21]
3 years ago
13

Which of the following expressions is equivalent to (13 + 2) (13 - 2)?

Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

d. 13^2 - 2^2

Step-by-step explanation:

The product of a sum and a difference is a difference of squares.

(13 + 2)(13 - 2) = 13^2 - 2^2

Answer: d. 13^2 - 2^2

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Line k is graphed at right.
saw5 [17]

Answer:

See below ↓↓

Step-by-step explanation:

<u>Equation of line k</u>

  • y = mx + b
  • m = Δy/Δx (ratio of change in y to change in x) = 2/3
  • b = 3 (as y-intercept is [0,3])
  • ⇒ y = 2/3x + 3

<u />

<u>a. parallel line</u>

  • For parallel lines, slope (m) remains the same, but the y-intercept (b) changes
  • ⇒ <u>y = 2/3x + 1</u>

<u></u>

<u>b. perpendicular line</u>

  • For perpendicular lines, the slope (m) is the negative reciprocal of the original line and the value of b stays the same [it can be any point as long as it intersects the line]
  • ⇒ <u>y = -3/2x + 1</u>
5 0
2 years ago
17 part A and B if you can help
dybincka [34]
Well maybe you could draw a little cup of raisins label it it 1 1/4 and multiply that be 5
4 0
3 years ago
What expressions are equivalent to 20
Diano4ka-milaya [45]

Answer:

What expressions are equivalent to 20

Step-by-step explanation:

since you didn't .show a link this is my guess, i guess.

4x5=20

6 0
4 years ago
Please help
tatuchka [14]
The independent variable is the # of hrs.
the dependent variable is # of gallons.
the slope is -125.
the y intercept is 13000
3000
7 0
3 years ago
Read 2 more answers
Factor completely and then place the factors in the proper location on the grid a^2-a-20
Gnoma [55]

Answer:

(x-5)(x+4)

Step-by-step explanation:

We have the following quadratic equation

a^2-a-20

The factored expression will have the following form

(x+b)(x+c)

Where b and c are two real numbers which when added together result in -1, and multiplying them results in -20

b*c=-20\\b+c=-1

You can verify that the numbers that meet this condition are:

-5 and 4

Then the factors are:

(x-5)(x+4)

3 0
3 years ago
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